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Mgcl2 contain molar mass=24.31+ 2(35.45)= 95.21
g/mol
124g of Mgcl2 contains moles= 95.21* 124=11806.04moles
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105 g of MgCl2 contains how much mol MgCl2?
First, we calculate the molar mass of MgCl2, which is 95.21 g/mol. Then, we divide the given mass by the molar mass to determine the number of moles of MgCl2. So, 105 g of MgCl2 contains approximately 1.10 moles of MgCl2.
What is the value of x When a 1.63 g sample of MgCl2xH2O is heated to remove all water a mass of 0.762 g remains?
You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O
How many moles are there in 0.684g MgCl2?
To find the number of moles in 0.684g of MgCl2, you need to divide the mass by the molar mass of MgCl2. The molar mass of MgCl2 is 95.211 g/mol (24.305 g/mol for Mg and 35.453 g/mol for Cl). Dividing 0.684g by 95.211 g/mol gives approximately 0.0072 moles of MgCl2.
What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
How many moles of MgCl2 are there in 317 g of the compound?
To find the number of moles of MgCl2 in 317 g of the compound, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to get the number of moles: 317 g / 95.21 g/mol = 3.33 moles of MgCl2.
What is the theory yield of magnesium chloride when 5.6 grams of magnesium is reacted with elemental chlorine there is an excess of elemental chlorine the 5.60g magnesium is the limiting reactant?
magnesium + chlorine --> magnesium chloride Mg (s) + Cl2 (g) --> MgCl2 (s) 5.60 g Mg x 1 mol Mg x 1 mol MgCl2 x 95.21 g MgCl2 = 21.9 g MgCl2 ..................24.31 g Mg. 1 mol Mg........ 1 mol MgCl2
What is the molarity of 0.96 g MgCl2 in 0.500 L of solution?
To find the molarity, first calculate the moles of MgCl2 using its molar mass. Molar mass of MgCl2 = 95.21 g/mol Moles of MgCl2 = 0.96 g / 95.21 g/mol = 0.0101 mol Then, divide the moles by the volume in liters to find molarity: Molarity = 0.0101 mol / 0.500 L = 0.0202 M.
What is the mass of 1.5 moles of MgCl2?
The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl21.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
How many formula units make up 11.6g of mgcl2?
To find the number of formula units of MgCl2 in 11.6g, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to find the number of moles (0.122 mol). Since 1 mol of MgCl2 contains 1 formula unit, the number of formula units in 11.6g of MgCl2 is also 0.122 mol.
What is the molecular weight for MgCl2?
The molecular weight of MgCl2 (magnesium chloride) is approximately 95.21 g/mol. This is calculated by adding the atomic weights of one magnesium atom (24.31 g/mol) and two chlorine atoms (35.45 g/mol each).
How many moles in 53.8 g of magnesium chloride?
To determine the number of moles in 53.8 g of magnesium chloride, you first need to calculate the molar mass of MgCl2 which is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 53.8 g / 95.21 g/mol = 0.565 moles.
Are 50 grams of NaCl and 50 grams of MgCl2 the same amount?
No, there will be more molecules in the 50 grams of NaCl, because its molacular weight is lower. NaCl has a molaculair mass of 58.44 g/mol and MgCl2 has a molcular mass of 95.21 g/mol. 50 g / 58.44 g/mol = 0.86 mol NaCl 50 g / 95.21 g/mol = 0.53 mol MgCl2 The avogadro contstant states that 1 mole equals 6.02214179*1023 molecules. So you have 0.86 * 6.022*1023 = 5.18*1023 molecules of NaCl and 0.53 * 6.022*1023 = 3.19*1023 molecules of MgCl2.
