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How many moles of MgCl2 are there in 317 g of the compound?
To find the number of moles of MgCl2 in 317 g of the compound, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to get the number of moles: 317 g / 95.21 g/mol = 3.33 moles of MgCl2.
How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
What is the molarity of a solution that is made by dissolving 75.0 grams of MgCl2 in 500.0 milliliters of solution?
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------
What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
In the reaction mgcl2 plus 2koh mgoh2 plus 2kcl how many moles of koh react with 1 mole of mgcl2?
1 mole of MgCl2 requires 2 moles of KOH to react based on the balanced chemical equation provided.
How many moles of MgCl2 are there in 313 g of the compound?
Approx 3.29 moles.
How many moles of MgCl2 are there in 317 g of the compound?
To find the number of moles of MgCl2 in 317 g of the compound, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to get the number of moles: 317 g / 95.21 g/mol = 3.33 moles of MgCl2.
How many moles are in 2 Na3PO4 3 MgCl2--Mg3PO42 6NaCl?
12 moles
How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
How many atoms are n 4.0 moles of MgCl2?
MgCl2 is an ionic compound with the Mg2+ cation and the Cl- anion in a 1:2 ratio. In each formula unit of MgCl2 there are two Mg2+ and one Cl- ion. So in 4 moles of MgCl2 there will be 12 moles of ions.
What is the molarity of a solution that is made by dissolving 75.0 grams of MgCl2 in 500.0 milliliters of solution?
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------
What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
In the reaction mgcl2 plus 2koh mgoh2 plus 2kcl how many moles of koh react with 1 mole of mgcl2?
1 mole of MgCl2 requires 2 moles of KOH to react based on the balanced chemical equation provided.
How many grams of MgCl2 are needed to make 700.mL of a 1.4 M solution?
To determine the grams of MgCl2 needed for a 1.4 M solution in 700 mL, we first calculate the moles of MgCl2 required using the formula Molarity (M) = moles/volume(L). Moles = Molarity x Volume(L). Moles = 1.4 mol/L x 0.7 L = 0.98 moles. Next, we calculate the molar mass of MgCl2 (95.21 g/mol) and then multiply the moles by the molar mass to find the grams needed: 0.98 moles x 95.21 g/mol = 93.3 grams of MgCl2.
How many moles of MgCl2 are present in 90.0 mL of 0.200 M MgCl2 solution?
To find the number of moles, first calculate the moles of MgCl2 in 90.0 mL of 0.200 M solution: moles = volume (L) * molarity moles = 0.090 L * 0.200 mol/L = 0.018 moles Therefore, there are 0.018 moles of MgCl2 present in 90.0 mL of 0.200 M MgCl2 solution.
What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
In the reaction MgCl2 plus 2KOH and 65532 Mg(OH)2 plus 2KCl how many moles of KOH react with 1 mole of MgCl2?
From the balanced equation it can be seen that it takes 2 moles KOH to react with each 1 mole of MgCl2. So, the answer is 2.
