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7.184119315x10^-3
Jessa Lorenzana
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∙ 10y ago95.2 g/mole
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How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
What is the molarity of 80g magnesium chloride dissolved in 250ml of water?
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
In the reaction mgcl2 plus 2koh mgoh2 plus 2kcl how many moles of koh react with 1 mole of mgcl2?
2
What is the molarity of a solution that is made by dissolving 75.0 grams of MgCl2 in 500.0 milliliters of solution?
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------
In the reaction MgCI2 plus 2KOH Mg(OH)2 plus 2KCI if 6 moles mgci2 are added to 6 moles koh which is the limiting reagent?
MgCl2 would be the limiting reagent
How many moles of MgCl2 are present in 20.0 mL of 0.800 M MgCl2 solution?
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
How many moles of MgCl2 are there in 313 g of the compound?
Approx 3.29 moles.
How many atoms are n 4.0 moles of MgCl2?
MgCl2 is an ionic compound with the Mg2+ cation and the Cl- anion in a 1:2 ratio. In each formula unit of MgCl2 there are two Mg2+ and one Cl- ion. So in 4 moles of MgCl2 there will be 12 moles of ions.
What is the molarity of 80g magnesium chloride dissolved in 250ml of water?
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
How many moles are in 2 Na3PO4 3 MgCl2--Mg3PO42 6NaCl?
12 moles
How many moles are contained in 444 grams of magnesium chloride?
Formula mass of MgCl2 = 24.3+2(35.5) = 95.3Amount of MgCl2 = 444/95.3 = 4.66mol4.66 moles of MgCl2 are contained within a 444g pure sample.
In the reaction mgcl2 plus 2koh mgoh2 plus 2kcl how many moles of koh react with 1 mole of mgcl2?
2
What is the molarity of a solution that is made by dissolving 75.0 grams of MgCl2 in 500.0 milliliters of solution?
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------
In the reaction MgCI2 plus 2KOH Mg(OH)2 plus 2KCI if 6 moles mgci2 are added to 6 moles koh which is the limiting reagent?
MgCl2 would be the limiting reagent
What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?
6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
In the reaction MgCl2 plus 2KOH and 65532 Mg(OH)2 plus 2KCl how many moles of KOH react with 1 mole of MgCl2?
From the balanced equation it can be seen that it takes 2 moles KOH to react with each 1 mole of MgCl2. So, the answer is 2.
How many formula units make up 11.6g of mgcl2?
Magnesium chloride (MgCl2) has a molecular weight of 95.21 grams per mole. 11.6 grams of MgCl2 is therefore .122 moles.
