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# How many moles of MgCl2 are present in 90.0 mL of 0.200 M MgCl2 solution?

Updated: 8/10/2023

Wiki User

14y ago

You have 2 litres. You need to divide 91 by 2 to get it per litre. 91/2 is 45.5g. 45.5 / 95.211. This gives you 0.477886 molar

Wiki User

10y ago

Wiki User

14y ago

.200 M means there are .200 moles in one liter. 90.0 ml is .0900 L. (.200 moles/liter)(.0900 L)= .0180 moles. 3 significant places.

Wiki User

8y ago

The answer is 0,009 moles for anhydrous MgCl2.

Wiki User

11y ago

2 Liters of Hotwater and 2 Oranges

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Q: How many moles of MgCl2 are present in 90.0 mL of 0.200 M MgCl2 solution?
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