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What reactant is limiting if 3000 cm3 of Cl2 at STP react with a solution containing 25 grams of NaBr?
Cl2 + 2NaBr => Br2 + 2NaCl
One mole Cl2 reacts with 2 moles NaBr
Cl2 = 71
NaBr = 102.9
Molar volume = 22.414 L/mole for ideal gas @STP
3L Cl2 = 3/22.414 = 0.1338 mole
25g NaBr = 25/102.9 = 0.2430 mole
0.1338 moles Cl2 requires 0.2676 moles NaBr for complete reaction
The NaBr is the limiting reagent
What else can I help you with?
What is the limiting reactant for the reaction below given that you start with 2.50 grams C and 2.50 grams SiO2?
To determine the limiting reactant, you need to compare the amount of product that each reactant could potentially produce. Calculate the moles of each reactant using their respective molar masses, and then find the mole ratio of C to SiO2 in the balanced chemical equation. Whichever reactant produces less product is the limiting reactant.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
How many grams of aluminum oxide can you make if you have 100 grams of aluminum combining with 50 grams of oxygen?
To find the amount of aluminum oxide that can be made, we need to determine the limiting reactant. The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. The molar mass of aluminum oxide is 101.96 g/mol. After determining the limiting reactant and doing the stoichiometry calculation, we find that 100 grams of aluminum can produce 197 grams of aluminum oxide in this reaction.
What is the maximum mass of aluminum chloride that can be formed when reacting 28.0g of aluminum with 33.0g of chlorine?
The formula of aluminium chloride is AlCl3. The atomic weight of aluminium is 27 and that of chlorine is 35.5. That means 35.5*3 grams of chlorine will combine with 27 grams of aluminium. So 33 grams of chlorine will combine with 8.37 grams of aluminium. The addition of both makes it 41.37 grams. In this reaction, the whole chlorine will be utilized and only part of the aluminium.
How many grams of calcium chloride will be produced when 30.0g of calcium carbonate are combined with 12.0g of hydrochloric acid?
Based on the chemical reaction: CaCO3 + 2HCl -> CaCl2 + CO2 + H2O Calculate the limiting reactant by converting each reactant to moles and comparing the ratios. The limiting reactant is calcium carbonate. Calculate the theoretical yield of calcium chloride using the stoichiometry of the reaction.
What is the limiting reactant when 3.14g of nitrogen react with 2.79g of hydrogen to produce ammonia and how many grams of ammonia are produce?
To determine the limiting reactant, we need to find the moles of each reactant. Then, we calculate the amount of ammonia that can be produced from each reactant. Whichever reactant produces the least amount of ammonia is the limiting reactant. Finally, we calculate the grams of ammonia produced based on the limiting reactant.
87.2 grams of glucose burned in 87.2 grams oxygen what is limiting reactant?
To determine the limiting reactant, you need to compare the amounts of reactants in terms of moles. First, convert the grams of glucose and oxygen into moles using their respective molar masses. Then, calculate the moles of products that can be formed from each reactant. The reactant that produces fewer moles of product will be the limiting reactant.
What is the limiting reactant for the reaction below given that you start with 2.50 grams C and 2.50 grams SiO2?
To determine the limiting reactant, you need to compare the amount of product that each reactant could potentially produce. Calculate the moles of each reactant using their respective molar masses, and then find the mole ratio of C to SiO2 in the balanced chemical equation. Whichever reactant produces less product is the limiting reactant.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
If 25.0 grams of potassium chlorate decomposes, how many grams of potassium chloride will be produced What is the limiting reactant?
I Don't knows Sorry
Which is none concentrated solution containing 5 grams of salt and 10 grams of water or a solution containing 18 grams of salt and 90 grams of water?
The more concentrated solution is the one containing 18 grams of salt and 90 grams of water. This is because the concentration of the solute (salt) is higher in this solution compared to the solution containing 5 grams of salt and 10 grams of water.
What is the limiting reagent for the reaction 4Al plus 3O2-2Al2 O3 given that you start with 10.0 grams of Al and 19.0 grams of O2?
To determine the limiting reagent, first convert the grams of each reactant to moles. Then, calculate the mole ratio between Al and O2 in the balanced equation. The reactant that produces fewer moles of product is the limiting reagent. In this case, compare the moles of Al and O2 to determine the limiting reagent.
What is the limiting reactant when 41.4 grams of cuo are exposed to 2.56 grams of h2 according to the equation cuo h2 yields cu h2o?
cuo
What is the limiting reactant of 6.5g of C3H8O and 12.3g of O2?
The reaction between Isopropyl alcohol and oxygen is 2 C3H8O + 9 O2 equals 6 CO2 + 8 H2O. So for every mole of isopropyl alcohol, 4.5 moles of oxygen are consumed. 6.5 grams of C3H8O is .108 moles and 12.3 grams of O2 is .384 moles. This means that O2 is the limiting reactant as it needs .486 moles of O2 to finish.
How many grams of aluminum oxide can you make if you have 100 grams of aluminum combining with 50 grams of oxygen?
To find the amount of aluminum oxide that can be made, we need to determine the limiting reactant. The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. The molar mass of aluminum oxide is 101.96 g/mol. After determining the limiting reactant and doing the stoichiometry calculation, we find that 100 grams of aluminum can produce 197 grams of aluminum oxide in this reaction.
What is the maximum mass of S8 that can be produced by combining 75 grams of each reactant?
The molar mass of S8 is 256 g/mol. To calculate the maximum mass of S8 that can be produced, first determine the limiting reactant by converting the masses of the reactants to moles. Then, use the stoichiometry of the reaction to find the mass of S8 produced from the limiting reactant.
What is the maximum mass of aluminum chloride that can be formed when reacting 28.0g of aluminum with 33.0g of chlorine?
The formula of aluminium chloride is AlCl3. The atomic weight of aluminium is 27 and that of chlorine is 35.5. That means 35.5*3 grams of chlorine will combine with 27 grams of aluminium. So 33 grams of chlorine will combine with 8.37 grams of aluminium. The addition of both makes it 41.37 grams. In this reaction, the whole chlorine will be utilized and only part of the aluminium.
