To find how many grams of iron can be produced, calculate the molar mass of Fe2S3 and C, then use stoichiometry to determine the amount of Fe that can be produced. 1 mole of Fe2S3 produces 2 moles of Fe, and 1 mole of C produces 3 moles of Fe, so compare the moles of Fe produced from each reactant and choose the limiting reactant. Calculate the amount of Fe produced.
To determine the limiting reactant, you need to compare the amounts of reactants in terms of moles. First, convert the grams of glucose and oxygen into moles using their respective molar masses. Then, calculate the moles of products that can be formed from each reactant. The reactant that produces fewer moles of product will be the limiting reactant.
I'm happy to help, but I need the specific reactions in question in order to provide a detailed calculation. Once you provide the reactions, I can assist you in determining the grams of the first reactant needed to react with 56.5 g of the second reactant.
To determine the limiting reactant, first convert the masses of both reactants to moles using their molar masses. Then, calculate the moles of products that can be formed from each reactant assuming complete reaction. The reactant that produces the lesser amount of product is the limiting reactant.
13.3g C + O2 = CO2 m(C)=4g => n(C)=4/12=0,333mol m(O2)=10.67g => n(O2)=10.67/28=0,381mol we have excess of oxigen n(CO2)=n(C)=0,333 m(CO2)=0.333*40=13.3g
To find the maximum number of grams of silver that can be produced, first calculate the moles of copper and silver nitrate using their respective molar masses. Then, determine the limiting reactant using the stoichiometry of the reaction. Finally, calculate the maximum number of grams of silver that can be produced by multiplying the moles of silver obtained from the limiting reactant by the molar mass of silver.
To determine the maximum amount of SO3 that can be produced, we need to find the limiting reactant first. Given 1.0g of S and 1.0g of O2, we calculate the number of moles for each reactant. Then, we find the mole ratio from the unbalanced equation and determine which reactant is limiting. Finally, we can calculate the maximum amount of SO3 that can be produced from the limiting reactant.
To determine the limiting reactant, we need to find the moles of each reactant. Then, we calculate the amount of ammonia that can be produced from each reactant. Whichever reactant produces the least amount of ammonia is the limiting reactant. Finally, we calculate the grams of ammonia produced based on the limiting reactant.
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
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To calculate the amount of AlO produced, you first need to determine the limiting reactant by converting the grams of Al and FeO to moles, then comparing their molar ratios. Once you find the limiting reactant, use stoichiometry to calculate the moles of AlO produced. Finally, convert the moles of AlO to grams. The same steps can be used to find the amount of Fe produced.
To find the limiting reactant, we need to determine how many grams of silver chloride can be produced from each reactant and compare the results. Calculate the amount of silver chloride that can be produced from 10.0 g of silver nitrate. Calculate the amount of silver chloride that can be produced from 15.0 g of barium chloride. The reactant that produces the lesser amount of silver chloride will be the limiting reactant.
The balanced chemical equation for the reaction is: 2Al + 3Cl₂ → 2AlCl₃ Calculate the limiting reactant: Moles of Al: 35.5g / molar mass of Al Moles of Cl₂: 39.0g / molar mass of Cl₂ Determine which reactant gives the lower amount of AlCl₃ produced. Once you know the limiting reactant, use stoichiometry to calculate the grams of AlCl₃ produced.
This question seems to be about the reactant side of a chemical equation. To calculate the mass of oxygen produced, you need to know the stoichiometry of the reaction. Without that information, it is not possible to determine why 160 grams of oxygen would be produced.
200
The amount of product produced by a chemical reaction depends on the stoichiometry of the reaction, which is given by the coefficients in the balanced equation. Without the balanced equation or additional information, it is not possible to determine the exact amount of product produced from a specific amount of reactant. You would need to know the stoichiometry of the reaction to calculate the amount of product.
To find the amount of aluminum oxide that can be made, we need to determine the limiting reactant. The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. The molar mass of aluminum oxide is 101.96 g/mol. After determining the limiting reactant and doing the stoichiometry calculation, we find that 100 grams of aluminum can produce 197 grams of aluminum oxide in this reaction.