0
What is the maximum mass of S8 that can be produced by combining 75 grams of each reactant?
The molar mass of S8 is 256 g/mol. To calculate the maximum mass of S8 that can be produced, first determine the limiting reactant by converting the masses of the reactants to moles. Then, use the stoichiometry of the reaction to find the mass of S8 produced from the limiting reactant.
What else can I help you with?
87.2 grams of glucose burned in 87.2 grams oxygen what is limiting reactant?
To determine the limiting reactant, you need to compare the amounts of reactants in terms of moles. First, convert the grams of glucose and oxygen into moles using their respective molar masses. Then, calculate the moles of products that can be formed from each reactant. The reactant that produces fewer moles of product will be the limiting reactant.
For each of the following precipitation reactions calculate how many grams of the first reactant are necessary to completely react with 56.5 g of the second reactant?
I'm happy to help, but I need the specific reactions in question in order to provide a detailed calculation. Once you provide the reactions, I can assist you in determining the grams of the first reactant needed to react with 56.5 g of the second reactant.
How many grams of iron can be made form 119 g of Fe2S3 and 12.7 g C?
To determine the amount of iron that can be produced from 119 g of Fe2S3 and 12.7 g of C, we first need to calculate the molar mass of Fe2S3 and C. The molar mass of Fe2S3 is approximately 207.9 g/mol, and the molar mass of C is approximately 12.01 g/mol. Next, we calculate the moles of Fe2S3 and C by dividing the given masses by their respective molar masses. Then, we determine the limiting reactant by comparing the moles of Fe2S3 and C. Finally, we use the stoichiometry of the balanced chemical equation to calculate the theoretical yield of iron, which is approximately 42.4 grams.
In a reaction 25 grams of reactant AB breaks down into 10 grams of product A and an unknown amount of product B. Using the law of conservation of mass how much does product B weigh?
According to the law of conservation of mass, the total mass of reactants must equal the total mass of products. In this case, the initial mass of reactant AB is 25 grams, and product A weighs 10 grams. Therefore, the mass of product B can be calculated as follows: 25 grams (mass of AB) - 10 grams (mass of A) = 15 grams. Thus, product B weighs 15 grams.
How many grams of barium sulfate can be produced from 20.8 grams of barium sulfate?
If you start with 20.8 grams of barium sulfate (BaSO₄), you cannot produce more barium sulfate from it; you can only measure how much you have. Therefore, you can produce a maximum of 20.8 grams of barium sulfate if you are referring to using the same amount of BaSO₄ in a reaction or process. In summary, you have 20.8 grams of barium sulfate available, not more.
If 34.5 g of copper reacts with 70.2g of silver nitrate according to the following reaction what is the maximum number of grams of silver that can be produced answer?
To find the maximum number of grams of silver that can be produced, first calculate the moles of copper and silver nitrate using their respective molar masses. Then, determine the limiting reactant using the stoichiometry of the reaction. Finally, calculate the maximum number of grams of silver that can be produced by multiplying the moles of silver obtained from the limiting reactant by the molar mass of silver.
What is the maximum amount in grams of SO3 that can be produced by the reaction of 1.0g of S with 1.0g of O2 via the equation belowS O2-- SO3 not balanced?
To determine the maximum amount of SO3 that can be produced, we need to find the limiting reactant first. Given 1.0g of S and 1.0g of O2, we calculate the number of moles for each reactant. Then, we find the mole ratio from the unbalanced equation and determine which reactant is limiting. Finally, we can calculate the maximum amount of SO3 that can be produced from the limiting reactant.
What is the limiting reactant when 3.14g of nitrogen react with 2.79g of hydrogen to produce ammonia and how many grams of ammonia are produce?
To determine the limiting reactant, we need to find the moles of each reactant. Then, we calculate the amount of ammonia that can be produced from each reactant. Whichever reactant produces the least amount of ammonia is the limiting reactant. Finally, we calculate the grams of ammonia produced based on the limiting reactant.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
If 25.0 grams of potassium chlorate decomposes, how many grams of potassium chloride will be produced What is the limiting reactant?
I Don't knows Sorry
If 108 grams of Al are allowed to completely react with 318 grams of FeO how many grams of AlO and Fe will be produced?
To calculate the amount of AlO produced, you first need to determine the limiting reactant by converting the grams of Al and FeO to moles, then comparing their molar ratios. Once you find the limiting reactant, use stoichiometry to calculate the moles of AlO produced. Finally, convert the moles of AlO to grams. The same steps can be used to find the amount of Fe produced.
How many grams of silver chloride are formed when 10.0 g of silver nitrate reacts with 15.0 g of barium chloride?
To find the limiting reactant, we need to determine how many grams of silver chloride can be produced from each reactant and compare the results. Calculate the amount of silver chloride that can be produced from 10.0 g of silver nitrate. Calculate the amount of silver chloride that can be produced from 15.0 g of barium chloride. The reactant that produces the lesser amount of silver chloride will be the limiting reactant.
How many grams of aluminum chloride could be produced from 35.5g of aluminum and 39.0g of chlorine gas?
The balanced chemical equation for the reaction is: 2Al + 3Cl₂ → 2AlCl₃ Calculate the limiting reactant: Moles of Al: 35.5g / molar mass of Al Moles of Cl₂: 39.0g / molar mass of Cl₂ Determine which reactant gives the lower amount of AlCl₃ produced. Once you know the limiting reactant, use stoichiometry to calculate the grams of AlCl₃ produced.
Why is 160 grams of oxygen mass would be produced?
This question seems to be about the reactant side of a chemical equation. To calculate the mass of oxygen produced, you need to know the stoichiometry of the reaction. Without that information, it is not possible to determine why 160 grams of oxygen would be produced.
In a chemical reaction 300 grams of reactant A are combined with 100 grams of reactant B . both A and B reactant to completion. how much will the product weigh?
200
If there are 4 grams of reactant how many grams of product are produced by the chemical reaction?
The amount of product produced by a chemical reaction depends on the stoichiometry of the reaction, which is given by the coefficients in the balanced equation. Without the balanced equation or additional information, it is not possible to determine the exact amount of product produced from a specific amount of reactant. You would need to know the stoichiometry of the reaction to calculate the amount of product.
How many grams of aluminum oxide can you make if you have 100 grams of aluminum combining with 50 grams of oxygen?
To find the amount of aluminum oxide that can be made, we need to determine the limiting reactant. The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. The molar mass of aluminum oxide is 101.96 g/mol. After determining the limiting reactant and doing the stoichiometry calculation, we find that 100 grams of aluminum can produce 197 grams of aluminum oxide in this reaction.
