0
What else can I help you with?
What is the Maximum number of grams of PH3 that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form PH3?
The balanced chemical equation for the reaction is 4P + 6H2 → 4PH3. Calculate the limiting reactant by converting the given masses of P and H2 to moles using their respective molar masses. Then, determine the maximum amount of PH3 that can be formed from the limiting reactant using the mole ratio from the balanced equation.
If an excess of nitrogen is reacted with 3.41 grams of hydrogen how many grams of ammonia can be produced?
Balanced equation first. N2 + 3H2 >> 2NH3 (hydrogen is limiting and drives the reaction ) 3.41 grams H2 (1mol/2.016g )(2mol NH3/3mol H2 )(17.034g NH3/1mol NH3 ) = 19.2 grams of ammonia produced ( this is called the Born-Haber process )
Maxium amount of Cu2s that can be formed if 42.35g Ni2S3 reacts with 66.01g CuNO3?
The balanced chemical equation for the reaction is 3Ni2S3 + 2Cu(NO3)2 → 6Cu2S + 3Ni(NO3)2. From the given weights, we first calculate the moles of each reactant, then determine the limiting reactant (Ni2S3 in this case). Using the stoichiometry from the balanced equation, the amount of Cu2S that can be formed from 42.35g of Ni2S3 is 42.35g * (6 mol Cu2S / 3 mol Ni2S3) = 84.7g Cu2S.
How many NO2 molecules would form as products if the reaction had a 75 percent yield?
If the reaction had a 75% yield, 75% of the theoretical maximum amount of NO2 molecules would be produced. To calculate the number of NO2 molecules formed, you would multiply the theoretical maximum by 0.75.
How do you calculate how many grams of water are produced from 22.1 grams of oxygen?
First find the percentage by mass of oxygen in water. The formula for water is H2O, showing that water contains two hydrogen atoms for every atom of oxygen. The gram atomic masses of hydrogen and oxygen are 1.00794 and 15.9994 respectively. Therefore, the percentage of oxygen in water is 100{15.9994/[15.9994 + 2(1.00794)]} or about 88.8 %, to the justified number of significant digits; the ratio of the maximum mass of water that can be made from a given mass of oxygen is 1/0.888 or about 1.126; and the answer to the question is this number multiplied by the stated mass of oxygen, or 24.9 grams, to the justified number of significant digits.
In the reaction sn plus 2hf -- snf2 plus h2 What is the maximum amount of snf2 that can be produced when 0.480 moles of sn are mixed with 0.720 moles of hf?
The balanced chemical equation shows a 1:1 ratio between Sn and SnF2. Since Sn is limiting in this reaction, the maximum amount of SnF2 that can be produced will be equal to the amount of Sn used, which is 0.480 moles. Therefore, 0.480 moles of SnF2 can be produced.
How many moles of hydrogen iodide are produced from 1 mole of iodine?
The balanced equation for the reaction between Iodine and Hydrogen is: H2 + I2 --> 2HI The ratio of I2 to HI is 1:2 Therefore 1 mole of Iodine can form a maximum of 2 moles of Hydrogen Iodide
What is the theoretical yield of a reaction Apex?
The theoretical yield of a reaction is the maximum amount of product that can be produced based on the stoichiometry of the balanced chemical equation. It is calculated using the mole ratio between the reactants and products, assuming complete conversion of the limiting reactant.
When 85.0 g of CH4 are mixed with 160 g of O2 what is the maximum amount of CO2 that can be produced?
The balanced chemical equation for the reaction of CH4 and O2 to produce CO2 is: CH4 + 2O2 -> CO2 + 2H2O First, calculate the limiting reactant by converting the given masses of CH4 and O2 to moles. Then, use the stoichiometry of the reaction to determine the maximum amount of CO2 that can be produced, based on the limiting reactant.
What mass of C3H3N can be made when 21.6g of C3H6 reacts with 21.6g of nitric oxide?
To find the mass of C3H3N produced, we first need to balance the chemical equation for the reaction between C3H6 and nitric oxide to yield C3H3N. Then, calculate the number of moles of C3H6 and nitric oxide from the given masses. Next, determine the limiting reactant to find the maximum amount of C3H3N produced. Finally, use the stoichiometry of the balanced equation to calculate the mass of C3H3N formed.
What is the theoretical yeild of HNO3?
The theoretical yield of HNO3 is the maximum amount of nitric acid that can be produced in a chemical reaction based on stoichiometry and assuming 100% yield. It can be calculated by converting the given amount of reactant to moles, using the balanced equation, and then converting moles to mass of HNO3.
The value obtained when an equation is used to calculate the amount of product that will form during a reaction?
The value obtained is the theoretical yield, which is the amount of product that should be obtained under ideal conditions according to the stoichiometry of the reaction. It represents the maximum amount of product that can be produced.
What is the Maximum number of grams of PH3 that can be formed when 6.2 g of phosphorus reacts with 4.0 g of hydrogen to form PH3?
The balanced chemical equation for the reaction is 4P + 6H2 → 4PH3. Calculate the limiting reactant by converting the given masses of P and H2 to moles using their respective molar masses. Then, determine the maximum amount of PH3 that can be formed from the limiting reactant using the mole ratio from the balanced equation.
What is the theoretical yield of CuCl?
The theoretical yield of CuCl can be calculated using the stoichiometry of the reaction it is produced in. For example, if CuCl is produced from the reaction of Cu with HCl, the balanced chemical equation can be used to determine the amount of CuCl that can be produced. Theoretical yield is the maximum amount of product that can be obtained under ideal conditions.
What is maximum mass of S8 that can be produced by combining 82.0g of each reactant 8SO2 16H2S yield 3S8 16H2O?
The molar mass of S8 is 256 g/mol. To find the maximum mass of S8 produced, calculate the number of moles of each reactant (4 moles for SO2 and 1 mole for H2S). Then, determine which reactant limits the mass of S8 produced by using the stoichiometry of the balanced chemical equation. In this case, 4 moles of SO2 will limit the production of S8, resulting in a maximum mass of 256g of S8 produced.
What does stoichiometric mean in chemistry?
Stoichiometry is about calculation of the quantities or relationship of between recant-ants and products in a chemical reaction. It is about calculation of moles, masses, and percents within a chemical equation.
What is the theoretical yield of potash alum in preparation of potash alum?
The theoretical yield of potash alum in a preparation reaction can be calculated using stoichiometry and the balanced chemical equation. The amount of potash alum produced will depend on the starting materials used and their quantities in the reaction. It is important to consider the limiting reactant to determine the maximum amount of product that can be formed.
