Every formula unit of sodium chloride has one sodium atom. Therefore, there are 4.0 moles of sodium ions in 4.0 moles of NaCl.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
40 g sodium chloride are easily soluble in water.The solubility of NaCl at 100 0C is 38,99 g/100 g NaCl.
.998 moles
2 moles 80/40= 2
Molartiy = moles of solute/Liters of solution200 mL X (1 Liter/10^2)= 0.200 Liters0.200 Liters x (0.05 M)= .01 moles of NaOH.01 moles of NaOH x (40 g NaOH/ 1 mole NaOH)= 0.4 g NaOH are required
The answer is 2337,59 g NaCl.
1
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
The molecular weight of sodium hydroxide is 40g/mol. To get the amount of moles, you have to divide the weight by molecular mass. 12g / 40 is 0.3 moles. This is 300 millimoles.
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
40 g sodium chloride are easily soluble in water.The solubility of NaCl at 100 0C is 38,99 g/100 g NaCl.
.998 moles
2 moles 80/40= 2
The common serving size is 0,5-1 g NaCl; sodium is 40 %.
40 moles of LiOH
NaOH = 40 Mwt so 15/40 moles present. This requires 15/40 moles of HNO3 from the above equation. The HNO3 contains 2 moles in 1000 ml and so 1 mole in 500 ml and therefore 500 x 15/40 = 137.5 mls required