Acids and Bases

# How many moles of HCl are present in 40ml of a 0.035M solution?

012

###### 2012-04-03 20:55:50

Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters)

algebraically manipulated,

Moles of solute = Liters of solution * Molarity

Moles HCl = (0.04 Liters)(0.035 M)

= 0.0014 moles HCl

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