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What is the answer of what is the weight percent of potassium nitrate in a solution that is made by dissolving 30.0 g of potassium nitrate in 90.0 g of water?
To find the weight percent of potassium nitrate in the solution, first calculate the total mass of the solution, which is the sum of the mass of potassium nitrate and the mass of water: 30.0 g + 90.0 g = 120.0 g. Next, use the formula for weight percent: (mass of solute / total mass of solution) × 100%. Thus, the weight percent of potassium nitrate is (30.0 g / 120.0 g) × 100% = 25.0%.
What mass of solution would result if 81g of glucose(C6H12O6) is added to enough water to make a solution of 15.0 percent by mass?
To determine the mass of the solution, we need to calculate the total mass of the solution when 81g of glucose is added. Since the solution is 15.0% glucose by mass, the remaining 85.0% is water. Therefore, the total mass of the solution can be calculated using the mass of glucose added and the percentage of water. This would result in a total mass of solution greater than 81g due to the addition of water to dissolve the glucose.
What is the change in weight of sac 1 containing 40 percent glucose suspended in distilled water?
The weight change of sac 1 containing 40 percent glucose suspended in distilled water will depend on the osmotic pressure gradient between the sac's contents and the surrounding solution. If the distilled water outside the sac is hypotonic compared to the glucose solution inside, water will move into the sac, causing it to gain weight. Conversely, if the external solution is hypertonic, water will exit the sac, resulting in weight loss. The actual change will depend on the specific conditions and volumes involved.
What is the final percent concentration of the solution when 600 ml of 100 percent methanol added to 4400 ml of water?
The final percent concentration of the solution would be approximately 12.0% methanol. This is calculated by dividing the volume of methanol by the total volume of the solution (600 ml / 5000 ml) and then multiplying by 100 to get the percentage.
The molarity of a 5 percent solution of NH3 in water?
The molarity of a 5% solution of NH3 in water depends on the density and molecular weight of NH3. Without this information, it is not possible to calculate the molarity.
How much water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution?
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
How much water added to convert a 10 percent solution to 02 percent solution?
add 4 parts water per part solution
How much water must be added to 12 L of a 40 percent solution of alcohol to obtain a 30 percent solution?
4 litres
A 280 mL solution is 20 percent salt How much water should be added to make the solution 14 percent salt?
98 mL
How do make a percent sucrose solution?
To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).
What is the answer of what is the weight percent of potassium nitrate in a solution that is made by dissolving 30.0 g of potassium nitrate in 90.0 g of water?
To find the weight percent of potassium nitrate in the solution, first calculate the total mass of the solution, which is the sum of the mass of potassium nitrate and the mass of water: 30.0 g + 90.0 g = 120.0 g. Next, use the formula for weight percent: (mass of solute / total mass of solution) × 100%. Thus, the weight percent of potassium nitrate is (30.0 g / 120.0 g) × 100% = 25.0%.
How much water will be there in a dilute acid in percentage?
well in dilute acid there is 1-10 percent and there will be only 90 percent of water so i was told from a science teacher who studied this
How much of a 50 percent solution should be added to 1 liter to make a 25 percent solution?
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
How much water must be added to 12 grams of a 90 percent iodine solution to produce a 25 percent iodine solution?
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
How much water should be added to 15 g of salt solution to obtain 15 percent salt solution?
Dissolve 15 g salt in 100 mL water.
If a water solution has some solids which are not dissolved what simple experiment would you conduct to tell in the percent of solids in the water by weight?
Simplest experiment is to take this water solution having undissolved solids in a hundred ml graduated cylinder upto its mark(100ml). Allow to stand for about half an hour, then note the level of undissolved solids at the bottom of the cylinder. Read that level as percent of solids in the water by weight. To determine percentage of solids by weight: Find the weight of water+undissolved solids Filter water solution through a filter paper. Find the weight of filtered water. Find the weight of dried solids. Percentage of undissolved solids = wt of undissolved solids divided by total weight of water and solids multiplied by 100
How much water must be added to a gallon of 10 percent saline solution to create a 2 percent solution?
There is 1 gallon of 10% solution...There is 0% saline in water...The equation is (0.1)(1) + 0x = 0.02 (x+1)...Answer is: 4 gallons. Hope I helped!!:)
