About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
Assuming that is is a solution of glucose in water, the answer is 93%.
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
Very simply 2g of ferric chloride and 100g (100ml) of water!
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
Simplest experiment is to take this water solution having undissolved solids in a hundred ml graduated cylinder upto its mark(100ml). Allow to stand for about half an hour, then note the level of undissolved solids at the bottom of the cylinder. Read that level as percent of solids in the water by weight. To determine percentage of solids by weight: Find the weight of water+undissolved solids Filter water solution through a filter paper. Find the weight of filtered water. Find the weight of dried solids. Percentage of undissolved solids = wt of undissolved solids divided by total weight of water and solids multiplied by 100
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
add 4 parts water per part solution
13.6% methanol solution.
4 litres
98 mL
Assuming that is is a solution of glucose in water, the answer is 93%.
75 litres
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
Dissolve 15 g salt in 100 mL water.
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
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