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How much water will be there in a dilute acid in percentage?
well in dilute acid there is 1-10 percent and there will be only 90 percent of water so i was told from a science teacher who studied this
If a water solution has some solids which are not dissolved what simple experiment would you conduct to tell in the percent of solids in the water by weight?
Simplest experiment is to take this water solution having undissolved solids in a hundred ml graduated cylinder upto its mark(100ml). Allow to stand for about half an hour, then note the level of undissolved solids at the bottom of the cylinder. Read that level as percent of solids in the water by weight. To determine percentage of solids by weight: Find the weight of water+undissolved solids Filter water solution through a filter paper. Find the weight of filtered water. Find the weight of dried solids. Percentage of undissolved solids = wt of undissolved solids divided by total weight of water and solids multiplied by 100
A chemist has m gm of salt water that is m percent salty so how many gram of salt must be added to make a solution that is 2m percent salty?
To convert the solution from m percent salty to 2m percent salty, you need to add m/2 grams of salt. This will ensure that the ratio of salt to water in the solution is doubled, resulting in a 2m percent salty solution.
How would you make 22.3 percent salt solution?
To make a 22.3% salt solution, you would dissolve 22.3 grams of salt in 100 grams of solution (salt + water). This would result in a solution where 22.3% of the total weight is salt.
When each what is added to water is the resulting solution acidic basic or neutral?
When each of the following is added to water, is the resulting solution acidic, basic, or neutral? a) HClO, b) NaCl, c) HCN, d) MgO, e) CH3OH
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
How much water added to convert a 10 percent solution to 02 percent solution?
add 4 parts water per part solution
How much water must be added to 12 L of a 40 percent solution of alcohol to obtain a 30 percent solution?
4 litres
A 280 mL solution is 20 percent salt How much water should be added to make the solution 14 percent salt?
98 mL
How do make a percent sucrose solution?
To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).
What is the answer of what is the weight percent of potassium nitrate in a solution that is made by dissolving 30.0 g of potassium nitrate in 90.0 g of water?
To find the weight percent of potassium nitrate in the solution, first calculate the total mass of the solution, which is the sum of the mass of potassium nitrate and the mass of water: 30.0 g + 90.0 g = 120.0 g. Next, use the formula for weight percent: (mass of solute / total mass of solution) × 100%. Thus, the weight percent of potassium nitrate is (30.0 g / 120.0 g) × 100% = 25.0%.
How much water will be there in a dilute acid in percentage?
well in dilute acid there is 1-10 percent and there will be only 90 percent of water so i was told from a science teacher who studied this
How much of a 50 percent solution should be added to 1 liter to make a 25 percent solution?
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
How much water must be added to 12 grams of a 90 percent iodine solution to produce a 25 percent iodine solution?
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
How much water should be added to 15 g of salt solution to obtain 15 percent salt solution?
Dissolve 15 g salt in 100 mL water.
If a water solution has some solids which are not dissolved what simple experiment would you conduct to tell in the percent of solids in the water by weight?
Simplest experiment is to take this water solution having undissolved solids in a hundred ml graduated cylinder upto its mark(100ml). Allow to stand for about half an hour, then note the level of undissolved solids at the bottom of the cylinder. Read that level as percent of solids in the water by weight. To determine percentage of solids by weight: Find the weight of water+undissolved solids Filter water solution through a filter paper. Find the weight of filtered water. Find the weight of dried solids. Percentage of undissolved solids = wt of undissolved solids divided by total weight of water and solids multiplied by 100
How much water must be added to a gallon of 10 percent saline solution to create a 2 percent solution?
There is 1 gallon of 10% solution...There is 0% saline in water...The equation is (0.1)(1) + 0x = 0.02 (x+1)...Answer is: 4 gallons. Hope I helped!!:)
