I suppose that this situation is not possible.
You can calculate the concentration of a phosphoric acid solution by determining the volume of sodium hydroxide needed to neutralize it in a titration. The molarity of the sodium hydroxide solution and the balanced chemical equation for the reaction will allow you to find the moles of phosphoric acid present, hence the concentration.
Lemonade made from a powdered mixture forms a solution because the powdered ingredients dissolve completely into the liquid, creating a homogenous mixture where all components are evenly distributed at a molecular level. In contrast, a suspension would have visible particles that do not dissolve and settle out over time.
In dilute sugar solution , the amount of water or solvent is more and hence it is a hypotonic solution.Therefore water will move from a region of higher concentration ( solution) to the dry apricots ( region of lower concentration).Hence , there wil be water content in the dry apricos and therefore it swells.
3 litres equal 3000 ml hence, 3l 400 ml is equal to 3400 ml
An isotonic solution is one in which the ionic environment is similar to that of the cytoplasm. Hence, when a cell is placed in an isotonic solution, there is no net diffusion of water into or out of the cell. The cell remains intact.
The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.
The molarity of the solution is calculated using the formula: Molarity (M) = moles of solute / liters of solution. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, plug in the values: M = 2.5 moles / 0.5 L = 5 M. Hence, the molarity of the solution is 5 M.
Urea has the formula (NH2)2CO, which equates to (14 + 2)2 +(12+16)= 32+28 = 60g Hence, 30g of urea is 0.5 mols.
You can calculate the concentration of a phosphoric acid solution by determining the volume of sodium hydroxide needed to neutralize it in a titration. The molarity of the sodium hydroxide solution and the balanced chemical equation for the reaction will allow you to find the moles of phosphoric acid present, hence the concentration.
To find the molarity, first calculate the number of moles of HCl using its molecular weight (36.46 g/mol). The number of moles is 10.0 g / 36.46 g/mol = 0.274 moles. Then, divide the number of moles by the volume of the solution in liters (250 mL = 0.25 L) to get the molarity: 0.274 moles / 0.25 L = 1.096 M. Thus, the molarity of the HCl solution is 1.096 M.
The molar mass of sodium chloride (NaCl) is 58.44 g/mol. First, calculate the number of moles of NaCl in 117 grams: 117 g / 58.44 g/mol = 2 moles. Next, calculate the molarity: 2 moles / 40.0 L = 0.05 M. Hence, the molarity of the solution is 0.05 M.
Given that 200cm3 yieded 20g.therefore 22400cm3 which is the volume occupied by gas at s.t.p will contained:(22400cm3 times 20g) divided by 200cm3,which equals 2240g.but molarity is mass conc./molar mass,here molar mass of NaOH is 40.Hence the molarity is:2240/40 which equals to 56moles/g.
To find the molarity of 48.6 grams of magnesium, you first need to determine the number of moles of magnesium in 48.6 grams using the molar mass of magnesium (24.305 g/mol). Then, you divide the moles of magnesium by the volume of the solution in liters to get the molarity.
Molar concentration in both base solutions NH3 and NaOH is assumed to be (equal) 0.1 mol Base/LWeak base like ammonia (NH3) with pKb = 9.2 and concentration (assumed) Cb = 0.1 (mol/L)pOH = 0.5*[pKb + pCb] = 0.5*[9.2 + 1.0] = 5.1 , hence [OH-] = 7.9*10-6pH = 14 - pOH = 8.9 hence [H+]= 1.3*10-9Strong base hydroxide (like from NaOH) with concentration (equally assumed) Cb = 0.1 (mol/L)pOH = 1.0 because [OH-] = 0.1pH = 13.0 hence [H+]= 1.0*10-13
The natural rate of unemployment cannot equal zero, because there will always be people seeking full time employment, because they are dissatisfied with their present job, or are newly in the workforce, etc. and hence are unemployed.
No solution. The two lines are parallel and hence never intersect hence no solution.
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