Remember the moles eq'n
Moles = mass(g) / Ar (Realtive Atomic Mass.
Mass = 48.6 g
Ar = 24 ( From Periodic Table ).
Hence
Moles = 48.6/24
Moles = 2.025
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
grams divided by the molecular weight to get to moles moles divided by volume to get molarity
The molarity of the solution is 0.5 M.
The atomic mass of magnesium (Mg) is approximately 24.305 grams per mole.
Magnesium sulfide react with water.This is not solubilty and molarity cannot be applied.
Molarity= moles/Liters To change grams to moles you divide by the mole weight which is listed on the periodic table. Mol= grams/mol weight The Mole weight of Magnesium Chloride is 59.8 grams/mol Mol=128g/59.8 Mol=2.14 Now, you put the number of moles and Liters into the equation Molarity=2.14 mol/1L Molarity=2.14 So, the molarity is 2.14 M
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
0.486 of a kilogram = 486 grams
The molarity is 0,41 mol/L.
Molarity = Grams/(Molecular Weight X Volume)
Molarity = Grams/(Molecular Weight X Volume)
Molarity= mols/ L So, take 4.13g MgBr2 ( because Mg has a +2 charge and Bromide has a +1 charge) and divide it by 184.1 g MgBr2 which gives you .022 mols of MgBr2 then you divide .022 by 845 which gives you 2.65 M Molarity = 2.65M
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
2
To calculate the molarity of magnesium ions (Mg²⁺) in a solution, first, determine the number of moles of magnesium. The molar mass of magnesium is approximately 24.31 g/mol. Therefore, 48.6 g of Mg corresponds to about 2.00 moles (48.6 g ÷ 24.31 g/mol). Molarity (M) is calculated as moles of solute divided by liters of solution. Thus, the molarity of magnesium ions in 2 liters of water is 2.00 moles ÷ 2 L = 1.00 M.
If 1,1 is grams the molarity is 0,317.