750 L hydrogen gas at 0 0C and 1 at is equal to 33,44 moles.
Mass (g) = Mr * Moles If you rearrange it, you get Moles = Mass/Mr Working with a 2dp periodic table you get: Moles = 2/1.01 =1.98 There are 1.98 moles of hydrogen in 2g of H2 gas.
Ideal gas equation. PV = nRT ===============
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed
Since hydrogen is a gas, we would need more information to answer it. As chance wrote, you will need twice as much hydrogen as oxygen. However, in order to know what the volume of that hydrogen is, we also need to know the temperature and pressure so that we can use the universal gas law to get the answer.
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
To find the number of moles of hydrogen gas, we first need to convert the mass of hydrogen gas from grams to moles using the molar mass of hydrogen gas (2 g/mol). 5.04 grams of hydrogen gas is equal to 5.04 g / 2 g/mol = 2.52 moles of hydrogen gas.
You can determine the moles of HCl formed by using a balanced chemical equation for the reaction between hydrogen gas and chlorine. Calculate the stoichiometric ratio of hydrogen to HCl in the balanced equation to determine the moles of HCl formed from the given moles of hydrogen gas.
To find the number of moles of hydrogen gas, we first need to calculate the number of moles of chlorine gas using the ideal gas law formula (PV = nRT). Once we have the moles of chlorine gas, we can determine the moles of hydrogen gas needed for the reaction. In this case, the stoichiometry of the reaction states that 1 mole of chlorine gas reacts with 1 mole of hydrogen gas, so the required moles of hydrogen gas will be equal to the moles of chlorine gas.
Mass (g) = Mr * Moles If you rearrange it, you get Moles = Mass/Mr Working with a 2dp periodic table you get: Moles = 2/1.01 =1.98 There are 1.98 moles of hydrogen in 2g of H2 gas.
210.3 moles of H2 are contained in one gallon of H2O
To find the number of moles in 18.0 grams of hydrogen gas, you need to divide the given mass by the molar mass of hydrogen gas. The molar mass of hydrogen gas (H2) is about 2.016 grams/mol. So, 18.0 grams / 2.016 grams/mol ≈ 8.93 moles of hydrogen gas.
To find the volume of hydrogen gas produced, we first need to convert the mass of baking soda (645g) to moles. Then, using the balanced chemical equation for the reaction, we can determine the moles of hydrogen gas produced. Finally, using the ideal gas law at STP, we can convert the moles of hydrogen gas to liters.
The balanced equation for the synthesis of water from hydrogen and oxygen is: 2H2 + O2 --> 2H2O. If you have 1.4 moles of hydrogen, you will produce 1.4 moles of water because the molar ratio of hydrogen to water in this reaction is 2:2, which is the same as 1:1, which is the same as 1.4:1.4.
Ideal gas equation. PV = nRT ===============
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
2 moles of sodium will produce 1 mole of hydrogen gas according to the chemical equation 2Na + 2H2O → 2NaOH + H2. The molar mass of sodium is 23 g/mol and of hydrogen gas is 2 g/mol. Thus, 2 moles of sodium is 46 grams (2 moles * 23 g/mol), which will produce 2 moles of hydrogen gas.
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed