The balanced equation for the synthesis of water from hydrogen and oxygen is:
2H2 + O2 --> 2H2O. If you have 1.4 moles of hydrogen, you will produce 1.4 moles of water because the molar ratio of hydrogen to water in this reaction is 2:2, which is the same as 1:1, which is the same as 1.4:1.4.
i dont know dont you watch the news if you dont then you are aloser and stupid
Answer: 7 moles hydrogen and 3,5 moles oxygen.
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
Write out the equation first: 10H2 + 10O2 --> xH2O Since there are 2 moles of Hydrogen for every mole of Oxygen and equal moles of both are given, the Hydrogen limits the reaction as the limiting reactant. 10 moles of Hydrogen can make 10 moles of H2O with 5 moles of Oxygen left over. Think of it logically: H2 is two hydrogen atoms and water needs two hydrogen atoms, so it is a one-to-one reaction.
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
H2O is water. One mole of water contains 2 moles of hydrogen atoms. Therefore, 10.7 moles of water contain 21.4 moles of hydrogen atom.
the complete chemical reaction is one mole (6.022 x 1023 molecules) of O2(g) plus two moles of H2(g) combine to make one complete mole of H2O gas. the complete balanced equation is O2(g) + 2H2(g)-> 2H2O(g)
The balanced chemical equation for the reaction between oxygen and hydrogen is2H2 + 02 -> 2H2OThus 2.2 moles of oxygen reacts with 4.4 moles of hydrogen to form 4.4 moles of steam (water in gaseous state).The mass of H2O obtained is thus 4.4 x 18.0 = 79.2g.
Write out the equation first: 10H2 + 10O2 --> xH2O Since there are 2 moles of Hydrogen for every mole of Oxygen and equal moles of both are given, the Hydrogen limits the reaction as the limiting reactant. 10 moles of Hydrogen can make 10 moles of H2O with 5 moles of Oxygen left over. Think of it logically: H2 is two hydrogen atoms and water needs two hydrogen atoms, so it is a one-to-one reaction.
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
2H2 + O2 ---------------> 2H2O for every 2 moles of hydrogen that reacts, 2 moles of water are produced, thus a 1:1 ratio of water produced to hydrogen reacted. So:- 2.5 moles of hydrogen reacted will produce 2.5 moles of water
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
H2O is water. One mole of water contains 2 moles of hydrogen atoms. Therefore, 10.7 moles of water contain 21.4 moles of hydrogen atom.
the complete chemical reaction is one mole (6.022 x 1023 molecules) of O2(g) plus two moles of H2(g) combine to make one complete mole of H2O gas. the complete balanced equation is O2(g) + 2H2(g)-> 2H2O(g)
This reaction?? 2H2O -> 2H2 + O2 this would be one to one and you would get; 174.82 moles of water vapor Without an equation I do not really know what you mean.
If the reaction is 2H2 + O2 = 2H20 then varying the ratio doesn't really affect the reaction. Let's throw out a ratio...you've got 20 moles of H2 and 10 moles of O2, which will give you 20 moles of water. If you were to change that to 20 moles of H2 and 15 moles of O2, you're still going to get 20 moles of water...but you'll have five moles of O2 left over that can't react with anything because there's no hydrogen left. Conversely, if you have an overage of hydrogen you will theoretically be left with excess hydrogen...the reality of hydrogen is it's reactive enough it will go out looking for something to do, and you'll get a second compound.
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
4 moles of hydrogen atoms