The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
To produce 1 mol of water, 2 mol of hydrogen is needed. Therefore, to produce 7.5 mol of water, you would need 15 mol of hydrogen.
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
The formula for Oxygen gas is O2, and the formula for water is H2O. Each molecule of Oxygen gas can produce 2 molecules of water (with enough Hydrogen, of course). So, 2.5 moles of Oxygen gas would be required to produce 5.0 moles of water.
No, burning hydrogen produces only water, it does not produce carbon or carbon dioxide.
To determine the amount of calcium needed, you need to balance the chemical equation for the reaction between calcium and water. The equation is Ca + 2H2O → Ca(OH)2 + H2. Then, convert the mass of water to moles, use the stoichiometry of the balanced equation to find the moles of calcium required, and convert that to grams of calcium.
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.
To produce 1 mol of water, 2 mol of hydrogen is needed. Therefore, to produce 7.5 mol of water, you would need 15 mol of hydrogen.
A lot
The balanced chemical equation for the reaction of hydrogen and oxygen to form water is 2H2 + O2 -> 2H2O. Based on the equation, for every 2 grams of hydrogen, 64 grams of oxygen are needed to form 36 grams of water. Thus, if 8 grams of hydrogen react completely with 64 grams of oxygen, the total mass of water formed would be 36 grams.
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
This value is 0,2 g hydrogen.
To calculate the amount of hydrogen peroxide (H2O2) needed to make a 1.33 molal solution in 1500 ml of water, you first need to convert the volume of water to grams. Since the density of water is 1.0 g/ml, 1500 ml of water is equal to 1500 grams. Next, calculate the moles of H2O2 needed using the molality formula (molality = moles of solute / mass of solvent in kg). Then convert the moles to grams by multiplying by the molar mass of H2O2 (34.02 g/mol).
The formula for Oxygen gas is O2, and the formula for water is H2O. Each molecule of Oxygen gas can produce 2 molecules of water (with enough Hydrogen, of course). So, 2.5 moles of Oxygen gas would be required to produce 5.0 moles of water.
To find the mass of water containing 5.0 grams of hydrogen, we need to set up a proportion using the mass percentage of hydrogen in water. Since water is 11.2% hydrogen by mass, we can calculate the mass of water using the formula: (5.0 grams of hydrogen) / (11.2 grams of hydrogen per 100 grams of water) = x grams of water. Converting grams to kilograms, the mass of water containing 5.0 grams of hydrogen would be 5.0 g / 11.2% = 44.64 g. This figure converted to kilograms is 0.04464 kg.
Petrol contains about 84% carbon and 16% hydrogen by weight so a litre weighing 700 grams contains 588 grams of carbon and 112 grams of hydrogen. In the engine it would burn with 2464 grams of oxygen to produce 2156 grams of CO2 and 1008 grams of water (steam), which is normally invisible but can be seen in the exhaust gases from a cold engine.
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