To find the volume of hydrogen gas produced, we first need to convert the mass of baking soda (645g) to moles. Then, using the balanced chemical equation for the reaction, we can determine the moles of hydrogen gas produced. Finally, using the ideal gas law at STP, we can convert the moles of hydrogen gas to liters.
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
To calculate the amount of hydrogen gas produced, first determine the moles of potassium from the given mass. Then, use the balanced chemical equation of the reaction between potassium and water to find the moles of hydrogen gas produced. Finally, convert the moles of hydrogen gas to liters using the ideal gas law.
When 42.0 grams of baking soda (sodium bicarbonate, NaHCO3) decomposes, it produces 22.0 grams of sodium carbonate (Na2CO3) and 20.0 grams of carbon dioxide (CO2) gas.
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
I assume you mean excess hydrochloric acid. Balanced equation. 2Al + 6HCl = 2AlCl3 + 3H2 2.70 grams Al (1 mole Al/26.98 grams)(3 mole H2/2 mole Al)(2.016 grams/1 mole H2) = 0.303 grams hydrogen gas produced --------------------------------------------------
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
To calculate the amount of hydrogen gas produced, first determine the moles of potassium from the given mass. Then, use the balanced chemical equation of the reaction between potassium and water to find the moles of hydrogen gas produced. Finally, convert the moles of hydrogen gas to liters using the ideal gas law.
The molar mass of water is 18 g/mol. Since there are 2 hydrogen atoms in each water molecule, the molar mass of hydrogen is 2 g/mol. Therefore, 90 g of water contains 5 moles of water, which means 10 moles of hydrogen were produced. At STP, 1 mole of any gas occupies 22.4 liters, so 10 moles of hydrogen would occupy 224 liters.
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.
When 42.0 grams of baking soda (sodium bicarbonate, NaHCO3) decomposes, it produces 22.0 grams of sodium carbonate (Na2CO3) and 20.0 grams of carbon dioxide (CO2) gas.
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).
Liters can't be converted to grams. Liters measure volume, while grams measure mass.
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Liters can't be converted to grams. Liters measure volume, while grams measure mass.
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
an equation showing conservation of mass of reactants and products:2H2O --> 2H2 & O2what is the mass of the oxygen gas produced, from 178.8 g H2O , (using molar masses:178.8 g H2O @ (1mol O2)(@ 32.00 g/mol) / (2molH2O)(18.02g/mol) =your answer (4 sigfigs): 158.8 g O2178.8 g H2O ---> 20.0 H2 & 158.8 O2
Liters can't be converted to grams. Liters measure volume, while grams measure mass.