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How many liters of hydrogen gas at STP can be produced with 645 grams of baking soda?
To find the volume of hydrogen gas produced, we first need to convert the mass of baking soda (645g) to moles. Then, using the balanced chemical equation for the reaction, we can determine the moles of hydrogen gas produced. Finally, using the ideal gas law at STP, we can convert the moles of hydrogen gas to liters.
How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?
The reaction between potassium chlorate and oxygen gas generates potassium chloride and oxygen gas. Therefore, the amount of potassium chlorate produced from the reaction is equal to the amount of potassium chlorate that was used, which is 500 grams.
If 15 liters of propane are completely consumed how many grams of carbon dioxide are produced?
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
How many grams of oxygen are produced in the decomposition of 6.02g of potassium chlorate?
The decomposition of potassium chlorate produces oxygen gas and potassium chloride. The molar ratio of oxygen to potassium chlorate is 3:2. Therefore, to find the grams of oxygen produced, you would calculate (6.02g * 3 mol O2/2 mol KClO3) * molar mass of O2.
How many grams of potassium chloride are formed by the decomposition of excess potassium chlorate to yield 3.40 L of oxygen?
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
How many liters of hydrogen gas at STP can be produced with 645 grams of baking soda?
To find the volume of hydrogen gas produced, we first need to convert the mass of baking soda (645g) to moles. Then, using the balanced chemical equation for the reaction, we can determine the moles of hydrogen gas produced. Finally, using the ideal gas law at STP, we can convert the moles of hydrogen gas to liters.
If 25.0 grams of potassium chlorate decomposes, how many grams of potassium chloride will be produced What is the limiting reactant?
I Don't knows Sorry
How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?
The reaction between potassium chlorate and oxygen gas generates potassium chloride and oxygen gas. Therefore, the amount of potassium chlorate produced from the reaction is equal to the amount of potassium chlorate that was used, which is 500 grams.
If 15 liters of propane are completely consumed how many grams of carbon dioxide are produced?
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
A sample of 90 g water was decomposed using electrolysis How many liters of hydrogen where produced at STP?
The molar mass of water is 18 g/mol. Since there are 2 hydrogen atoms in each water molecule, the molar mass of hydrogen is 2 g/mol. Therefore, 90 g of water contains 5 moles of water, which means 10 moles of hydrogen were produced. At STP, 1 mole of any gas occupies 22.4 liters, so 10 moles of hydrogen would occupy 224 liters.
What is the formula for potassium hydrogen sulfide?
The formula for potassium hydrogen sulfide is KHS. Another name for this inorganic compound is potassium hydrosulfide. Its molar mass is 72.17 grams per mole, and it is soluble in water.
How many grams of water are produced when 300 grams of hydrogen react with an unlimited amount of oxygen?
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.
How many grams of oxygen are produced in the decomposition of 6.02g of potassium chlorate?
The decomposition of potassium chlorate produces oxygen gas and potassium chloride. The molar ratio of oxygen to potassium chlorate is 3:2. Therefore, to find the grams of oxygen produced, you would calculate (6.02g * 3 mol O2/2 mol KClO3) * molar mass of O2.
How many grams of potassium chloride are formed by the decomposition of excess potassium chlorate to yield 3.40 L of oxygen?
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
How much potassium bromide in grams should be added to water to prepare 0.50L of solution with a molarity of 0.125M?
To calculate the amount of potassium bromide needed, use the formula: moles = molarity x volume (in liters). First, convert the volume to liters by dividing 0.50L by 1000. Then, multiply the molarity (0.125M) by the volume in liters to find the moles of potassium bromide needed. Finally, convert moles to grams using the molar mass of potassium bromide (KBr).
What mass of water decomposes to make 4 grams of hydrogen gas and32 grams of oxygen gas how do you know?
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).
How many liters are in 43 grams of potassium nitrate?
The gram is unit of mass and the litre is a unit of volume.You can dissolve 45 g in what volume you want.
