If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
The balanced chemical equation for the combustion of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means that 5 moles of oxygen are required to completely combust 1 mole of propane. Therefore, 20 moles of oxygen would be produced from the complete combustion of 4 moles of propane.
Carbon dioxide is the gas that is the product of combustion of propane.
Smoke is produced when propene is burned due to incomplete combustion. This occurs when there is insufficient oxygen present to completely oxidize the propene molecule, leading to the formation of carbon particles that are visible as smoke.
This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.
The heat and light produced when burning propane come from the chemical reaction between propane and oxygen. This reaction releases energy in the form of heat and light as the propane molecules break apart and combine with oxygen to form carbon dioxide and water vapor.
The balanced chemical equation for the combustion of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means that 5 moles of oxygen are required to completely combust 1 mole of propane. Therefore, 20 moles of oxygen would be produced from the complete combustion of 4 moles of propane.
9 particles
Carbon dioxide is the gas that is the product of combustion of propane.
Combustion of propaneC3H8 + 5O2 ==> 3CO2 + 4H2OWhat is the question?
when you burn propane to complete combustion you will get a mixture of carbon dioxide and water vapor.
C3H8 + 5O2 -> 3CO2 + 4H2O That is the complete combustion for Propane.
Smoke is produced when propene is burned due to incomplete combustion. This occurs when there is insufficient oxygen present to completely oxidize the propene molecule, leading to the formation of carbon particles that are visible as smoke.
30 moles
The volume of CO2 is 4,94 L.
This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.
The heat and light produced when burning propane come from the chemical reaction between propane and oxygen. This reaction releases energy in the form of heat and light as the propane molecules break apart and combine with oxygen to form carbon dioxide and water vapor.
carbon dioxide and water oxygen gas and carbon atoms