The needed mass of sodium is 91,659 g (for 2 moles H2).
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
Since sodium chloride has equal parts of sodium and chlorine by weight, you would need 29.3 grams of sodium to create 29.3 grams of sodium chloride.
The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.
Sodium sulfate is not prepared from hydrogen chloride.
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
To calculate the number of moles in 454 grams of sodium, you need to divide the given mass by the molar mass of sodium. The molar mass of sodium is approximately 23 grams/mol. Therefore, 454 grams of sodium is equal to 454/23 = 19.74 moles of sodium.
The molar mass of sodium hydrogen carbonate (NaHCO3) is approximately 84 grams per mole. Therefore, the mass of 1.00 mole of sodium hydrogen carbonate would be 84 grams.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
12.01 g NH3 = 0.667 mol NH3 = 1 mol H2 = 2.0 g H2
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
Since sodium chloride has equal parts of sodium and chlorine by weight, you would need 29.3 grams of sodium to create 29.3 grams of sodium chloride.
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.
The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.
None. There is no hydrogen in sodium
molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride