12.01 g NH3 = 0.667 mol NH3 = 1 mol H2 = 2.0 g H2
530,3 g potassium iodide are needed.
290 grams
Voltage is electrical pressure and Joules is a power rating so other info is needed
2 grams is 2,000mg
2,957.177 grams.
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
A lot
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
800 g oxygen are needed.
530,3 g potassium iodide are needed.
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
To solve this, we will figure out how many grams there are per litre. To do this, we will divide the overall amount of litres 350 grams goes into by 350, so we are dividing 350 by 10,000. This answer is 0.035. We will then multiply 0.035 (how many grams needed for one litre) by 3300, to get how many are needed for that many litres, which gives us 115.5 grams. 115.5 grams are needed for 3300 litres if 250 grams are needed for 10,000 litres.
394.794 grams
About 245 grams.
1258
To produce 1 mole of chloroform, you need 3 moles of chlorine. So, to produce 1.5 moles of chloroform, you would need 4.5 moles of chlorine. Converting moles to grams by using the molar mass of chlorine (35.5 g/mol) gives you 160.5 grams of chlorine required.
To find the amount of aluminum needed to produce aluminum sulfate, you need to consider the molar mass of aluminum sulfate and the ratio of aluminum in the compound. First, calculate the molar mass of aluminum sulfate (Al2(SO4)3). Then, find the ratio of aluminum in the compound (2 moles of Al in 1 mole of Al2(SO4)3). Finally, use this information to calculate the grams of aluminum needed to produce 25.0 grams of aluminum sulfate.