136,315 g ZnCl are obtained.
The equation for the reaction is Zn + 2 HCl -> ZnCl2. The gram atomic masses of zinc and chlorine are 65.39 and 35.453 respectively. Therefore, the number of grams of zinc chloride that can be formed from 7.96 g of zinc is: 7.96{[65.39 + 2(35.453)]/65.39} or about 16.6 g of zinc chloride, to the justified number of significant digits.
To make 0.88 mol of ZnCl2, you would need an equal molar amount of AlCl3. The molar ratio between AlCl3 and ZnCl2 is 2:3. Therefore, you would need 0.88 mol * (2/3) = 0.59 mol of AlCl3. To convert this to grams, you would multiply by the molar mass of AlCl3.
The reaction of zinc with hydrochloric acid is simplified as Zn + 2 HCl = ZnCl2 + H2. This means for every mole of zing, 1 mole of ZnCl2 is formed. 4.96 grams zinc is equal to .0759 moles, so 5.17 grams of zinc chloride would be optimally produced.
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
The equation for the reaction is Zn + 2 HCl -> ZnCl2. The gram atomic masses of zinc and chlorine are 65.39 and 35.453 respectively. Therefore, the number of grams of zinc chloride that can be formed from 7.96 g of zinc is: 7.96{[65.39 + 2(35.453)]/65.39} or about 16.6 g of zinc chloride, to the justified number of significant digits.
To make 0.88 mol of ZnCl2, you would need an equal molar amount of AlCl3. The molar ratio between AlCl3 and ZnCl2 is 2:3. Therefore, you would need 0.88 mol * (2/3) = 0.59 mol of AlCl3. To convert this to grams, you would multiply by the molar mass of AlCl3.
The reaction of zinc with hydrochloric acid is simplified as Zn + 2 HCl = ZnCl2 + H2. This means for every mole of zing, 1 mole of ZnCl2 is formed. 4.96 grams zinc is equal to .0759 moles, so 5.17 grams of zinc chloride would be optimally produced.
25
20,1588 grams of hydrogen
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
None. When NH reacts there is no Pb involved and so there is none formed.
many, zinc oxide, zinc carbonate, zinc chloride...