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The formula given shows that each formula unit of KCl contains one atom of potassium. Therefore, the number of moles of potassium will be the same as the number of moles of KCl, and its gram formula mass is 74.55. therefore, the number of moles is 125/74.55 or 1.68, to the justified number of significant digits.
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How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
How many ml of 0.25M KCl are needed to provide 0.012 moles of KCl?
0.012mol KCl x (1L/0.25mol KCl) x (1000ml/1L) = 48 mL KCl
How many moles are in 74 g of KCl?
1 mole
How many grams of KCl are needed to make 100 ml of a 3.5M solution?
In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
How many moles of KCl are dissolved in 1.20 L of a 0.400 M KCl solution?
To calculate the amount of moles of potassium chloride in a 0.400 M KCl (aq) solution, you may use equation (1) belown = c * v (1)where n equals the amount of moles, c is the concentration of the solution and v is the volume.We have the volume and the concentration, which renders us able to solve the equation:n = 0.400 * 1.2 Ln = 0.48 moles.
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
How many moles of KCl are contained in 121mL of a 1.68M KCl solution?
Molarity is moles of solute per L of solution.moles KCl = ( 1.68 M ) ( 0.121 L ) = ( 1.68 mol/L ) ( 0.121 L )moles KCl = 0.203 moles KCl
How many moles of KCl in 0.90M KCl?
The answer is of course 0,9 M.
How many moles are in 12.57 grams of KC1?
12.57 grams KCl (1mol KCl/74.55g ) = 0.1686 moles
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
How many moles of KCL are present in 50.0ml of a 0.552 M solution?
Molarity = moles of solute/Liters of solution ( 50.0 ml = 0.05 Liters ) 0.552 M KCl = moles/.0.05 liters = 0.0276 moles of KCl
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
How many moles of KCl will be formed from 0.440 moles of KClO3?
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
How many moles are in 48g of KCl?
KCl has a molar mass of 39+35.5=74.5g/mol, and 48/74.5=0.64mol.
How many grams are in 3.75 moles of kcl?
279.56
How many moles of KCl are contained in a 0.630L of a 2.3M KCl solution?
2.3M means 2.3 moles per litre. Number of moles = 2.3mol/litre x 0.630litre = 1.449mols
