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How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
To calculate the grams of KCl needed, first determine the molar mass of KCl (74.55 g/mol). Then use the formula: grams = molarity x volume (L) x molar mass. Plugging in the values, you get: grams = 0.75 mol/L x 2.25 L x 74.55 g/mol = 126.60 grams of KCl.
How many mols in 74g of KCl?
1 mole.
How many moles of pottasium are in 125g of KCl?
The formula given shows that each formula unit of KCl contains one atom of potassium. Therefore, the number of moles of potassium will be the same as the number of moles of KCl, and its gram formula mass is 74.55. therefore, the number of moles is 125/74.55 or 1.68, to the justified number of significant digits.
How many grams of KCl to make 50 mL of 2.45 M KCl?
To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.
The molarity of a solution of 5.0 g of KCl in 100 mL of solution is?
To find the molarity, first calculate the number of moles of KCl using its formula weight. The formula weight of KCl is 74.55 g/mol. So, for 5.0 g of KCl, the number of moles is 5.0 g / 74.55 g/mol = 0.067 moles. Then, divide the moles by the volume of the solution in liters (100 mL = 0.1 L) to find the molarity: 0.067 moles / 0.1 L = 0.67 M.
How many grams are in 3.75 moles of kcl?
To find the number of grams in 3.75 moles of KCl, you would first calculate the molar mass of KCl, which is approximately 74.55 g/mol. Then, you would multiply this molar mass by the number of moles (3.75 moles) to get the answer, which is 279.56 grams of KCl.
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
To calculate the grams of KCl needed, first determine the molar mass of KCl (74.55 g/mol). Then use the formula: grams = molarity x volume (L) x molar mass. Plugging in the values, you get: grams = 0.75 mol/L x 2.25 L x 74.55 g/mol = 126.60 grams of KCl.
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
How many mols in 74g of KCl?
1 mole.
How many moles of pottasium are in 125g of KCl?
The formula given shows that each formula unit of KCl contains one atom of potassium. Therefore, the number of moles of potassium will be the same as the number of moles of KCl, and its gram formula mass is 74.55. therefore, the number of moles is 125/74.55 or 1.68, to the justified number of significant digits.
How many moles are in 12.57 grams of KC1?
To find the number of moles in 12.57 grams of KCl, you need to first calculate the molar mass of KCl which is approximately 74.55 g/mol. Then, divide the given mass (12.57g) by the molar mass to get the number of moles, which is approximately 0.1685 moles.
How many moles are in 550 grams of KCl?
To calculate the number of moles in 550 grams of KCl, first find the molar mass of KCl. Potassium (K) has a molar mass of 39.10 g/mol and chlorine (Cl) has a molar mass of 35.45 g/mol. Add these together to get the molar mass of KCl, which is 74.55 g/mol. Divide the given mass (550 grams) by the molar mass (74.55 g/mol) to find the number of moles. In this case, there are approximately 7.39 moles of KCl in 550 grams.
How many grams of KCl to make 50 mL of 2.45 M KCl?
To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.
How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution?
To calculate the amount of KCl needed, we first need to find the number of moles of KCl required using the formula: moles = Molarity x Volume (in L). Then, we convert moles to grams using the molar mass of KCl, which is 74.55 g/mol. Finally, we use the formula: grams = moles x molar mass to find that approximately 6.33 grams of KCl are needed to prepare 125 mL of a 0.720 M solution.
The molarity of a solution of 5.0 g of KCl in 100 mL of solution is?
To find the molarity, first calculate the number of moles of KCl using its formula weight. The formula weight of KCl is 74.55 g/mol. So, for 5.0 g of KCl, the number of moles is 5.0 g / 74.55 g/mol = 0.067 moles. Then, divide the moles by the volume of the solution in liters (100 mL = 0.1 L) to find the molarity: 0.067 moles / 0.1 L = 0.67 M.
How many grams of KCl are needed to make 100 ml of a 3.5M solution?
In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
How many grams of KCl would you need to make 250 ml of a 0.5-M Solution w work?
Molar mass of KCl = 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol. A 0.5 M solution is required (0.5 mol/L or 0.5 moles per litre). 0.5 moles of KCl is 0.5 mol x 74.5 g/mol = 37.25 g. Dissolving this 37.25 g of KCl in a litre of water would give a 0.5 M solution. If 1 L or 1000 mL of 0.5 M solution contains 0.5 moles then 1 mL of the same concentration solution would contain 0.5/1000 moles and 250 mL would contain 250 x 0.5/1000 moles = 0.125 moles. 0.125 moles of KCl is 0.125 mol x 74.5 g/mol = 9.31 g.
