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How many grams of KCl are needed to make 100 ml of a 3.5M solution?
In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
How many grams of KCl would you need to make 250 ml of a 0.5-M Solution w work?
Molar mass of KCl = 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol. A 0.5 M solution is required (0.5 mol/L or 0.5 moles per litre). 0.5 moles of KCl is 0.5 mol x 74.5 g/mol = 37.25 g. Dissolving this 37.25 g of KCl in a litre of water would give a 0.5 M solution. If 1 L or 1000 mL of 0.5 M solution contains 0.5 moles then 1 mL of the same concentration solution would contain 0.5/1000 moles and 250 mL would contain 250 x 0.5/1000 moles = 0.125 moles. 0.125 moles of KCl is 0.125 mol x 74.5 g/mol = 9.31 g.
How many atoms of K in 2.77g of KCl?
2.77 g KCl * x moles KCl/ 74.5 g/mol 0.0372 mol KCl * 1 mol K/ 1 mol Cl = 0.0372 mol K 0.0372 mol K * 6.02*10^23 2.24*10^22 atoms K
How many grams of KCL is produced from 2.5 g of K and 1 g of Cl?
1. 4.8 g of KCL 2. 2.1 g of KCL
What mass of KCl would be needed to form a saturated solution if the KCl was dissolved in 200 g of water at 80 C?
Minimum 102,6 g of KCl.
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
How many grams of KCl are needed to make 100 ml of a 3.5M solution?
In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
How many moles of potassium iodide are there in 50 grams?
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl
How many grams of KCl would you need to make 250 ml of a 0.5-M Solution w work?
Molar mass of KCl = 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol. A 0.5 M solution is required (0.5 mol/L or 0.5 moles per litre). 0.5 moles of KCl is 0.5 mol x 74.5 g/mol = 37.25 g. Dissolving this 37.25 g of KCl in a litre of water would give a 0.5 M solution. If 1 L or 1000 mL of 0.5 M solution contains 0.5 moles then 1 mL of the same concentration solution would contain 0.5/1000 moles and 250 mL would contain 250 x 0.5/1000 moles = 0.125 moles. 0.125 moles of KCl is 0.125 mol x 74.5 g/mol = 9.31 g.
What is the molarity of a solution made by dissolving 4.88 g of KCl in 423 mL of solution?
Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------
How many atoms of K in 2.77g of KCl?
2.77 g KCl * x moles KCl/ 74.5 g/mol 0.0372 mol KCl * 1 mol K/ 1 mol Cl = 0.0372 mol K 0.0372 mol K * 6.02*10^23 2.24*10^22 atoms K
How will prepare the 0.1N of KCL solution?
0.1 N KCl is the same as 0.1 M KCl. This requires one to dissolve 0.1 moles per each liter of solution. The molar mass of KCl is 74.6 g/mol. So 0.1 moles = 7.46 gDissolve 7.46 g KCl in enough water to make 1 liter (1000 ml)Dissolve 3.73 g KCl in enough water to make 0.5 liter (500 ml)Dissolve 0.746 g KCl in enough water to make 0.1 liter (100 ml)etc., etc.
How many grams of KCL is produced from 2.5 g of K and 1 g of Cl?
1. 4.8 g of KCL 2. 2.1 g of KCL
What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?
moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml = 0.25 L molarity = moles/liter = 1.34 moles/0.25 L = 5.37 M Since KCl dissociates completely into K+ and Cl-, you have 5.37 M of each = total of 10.74 osmolar
What is the mass of K2O contain equal number of moles of K atoms as are present in 1kg of KCl?
This mass is 631,75 g K2O.
How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution?
The answer is 6,71 g dried KCl.
