0.012mol KCl x (1L/0.25mol KCl) x (1000ml/1L) = 48 mL KCl
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Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
1. 4.8 g of KCL 2. 2.1 g of KCL
KCL is Potassium Chloride.
Depends what you measure. 74 grams of water is 6 tablespoons.
.003 mols .003 mols
0.012mol KCl x (1L/0.25mol KCl) x (1000ml/1L) = 48 mL KCl
The answer is of course 0,9 M.
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
you would get 6.4 mols of NaCl and 0.3 mols of unreacted Na
The answer is 6,71 g dried KCl.
49.03924
The answer is 9,92 moles.
0.006327754
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