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How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution?
To calculate the amount of KCl needed, we first need to find the number of moles of KCl required using the formula: moles = Molarity x Volume (in L). Then, we convert moles to grams using the molar mass of KCl, which is 74.55 g/mol. Finally, we use the formula: grams = moles x molar mass to find that approximately 6.33 grams of KCl are needed to prepare 125 mL of a 0.720 M solution.
How many moles of potassium iodide are there in 50 grams?
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl
How many moles are in 550 grams of KCl?
To calculate the number of moles in 550 grams of KCl, first find the molar mass of KCl. Potassium (K) has a molar mass of 39.10 g/mol and chlorine (Cl) has a molar mass of 35.45 g/mol. Add these together to get the molar mass of KCl, which is 74.55 g/mol. Divide the given mass (550 grams) by the molar mass (74.55 g/mol) to find the number of moles. In this case, there are approximately 7.39 moles of KCl in 550 grams.
Help with stoichiometry show steps How many grams of KClO3 must be decomposed to yield 30 grams of oxygen?
2 KClO3 -> KCL + 3O2 Molar weight of O2 = 32 grams/mole (so close it doesn't matter) 30 grams/32grams/mole = 0.9375 moles Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?) now if we have 3 moles of O2 then we have 2 moles of KCl. If we have one mole of O2 then we have 2/3 moles of KCL What ever moles we have of O2 we must multiply it by 2/3 to get the moles of KCl So we have 0.9375moles of O2 x 2/3 = 0.625 moles of KCl So 0.625 moles of KCl x 74.5 grams/mole KCl = 46.5625 grams KCl
How many moles are in 0.98 grams of Potassium chloride?
To determine the number of moles in 0.98 grams of Potassium chloride, you need to divide the given mass by the molar mass of Potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. So, 0.98 grams / 74.55 g/mol ≈ 0.013 moles of KCl.
How many moles are in 12.57 grams of KC1?
To find the number of moles in 12.57 grams of KCl, you need to first calculate the molar mass of KCl which is approximately 74.55 g/mol. Then, divide the given mass (12.57g) by the molar mass to get the number of moles, which is approximately 0.1685 moles.
How many grams of KCl to make 50 mL of 2.45 M KCl?
To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
To calculate the grams of KCl needed, first determine the molar mass of KCl (74.55 g/mol). Then use the formula: grams = molarity x volume (L) x molar mass. Plugging in the values, you get: grams = 0.75 mol/L x 2.25 L x 74.55 g/mol = 126.60 grams of KCl.
How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution?
To calculate the amount of KCl needed, we first need to find the number of moles of KCl required using the formula: moles = Molarity x Volume (in L). Then, we convert moles to grams using the molar mass of KCl, which is 74.55 g/mol. Finally, we use the formula: grams = moles x molar mass to find that approximately 6.33 grams of KCl are needed to prepare 125 mL of a 0.720 M solution.
How much 75.66MKCL is required toprepare 1L of solution?
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
How many moles of potassium iodide are there in 50 grams?
For this you need the atomic (molecular) mass of KCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. KCl= 74.6 grams50.0 grams KCl / (74.6 grams) = .670 moles KCl
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
How many moles are in 550 grams of KCl?
To calculate the number of moles in 550 grams of KCl, first find the molar mass of KCl. Potassium (K) has a molar mass of 39.10 g/mol and chlorine (Cl) has a molar mass of 35.45 g/mol. Add these together to get the molar mass of KCl, which is 74.55 g/mol. Divide the given mass (550 grams) by the molar mass (74.55 g/mol) to find the number of moles. In this case, there are approximately 7.39 moles of KCl in 550 grams.
Help with stoichiometry show steps How many grams of KClO3 must be decomposed to yield 30 grams of oxygen?
2 KClO3 -> KCL + 3O2 Molar weight of O2 = 32 grams/mole (so close it doesn't matter) 30 grams/32grams/mole = 0.9375 moles Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?) now if we have 3 moles of O2 then we have 2 moles of KCl. If we have one mole of O2 then we have 2/3 moles of KCL What ever moles we have of O2 we must multiply it by 2/3 to get the moles of KCl So we have 0.9375moles of O2 x 2/3 = 0.625 moles of KCl So 0.625 moles of KCl x 74.5 grams/mole KCl = 46.5625 grams KCl
How many moles are in 0.98 grams of Potassium chloride?
To determine the number of moles in 0.98 grams of Potassium chloride, you need to divide the given mass by the molar mass of Potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. So, 0.98 grams / 74.55 g/mol ≈ 0.013 moles of KCl.
How many moles of KCl are contained in 121mL of a 1.68M KCl solution?
Molarity is moles of solute per L of solution.moles KCl = ( 1.68 M ) ( 0.121 L ) = ( 1.68 mol/L ) ( 0.121 L )moles KCl = 0.203 moles KCl
