In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg
298g KCl
molarity = moles of solute
Liters of solution
1.00M = x mol
4.00 L
4 mol KCl is 298g KCl (molar mass = 74.5g)
dissolve 26.075g KCL and make final volume 100ml. The final product will be 3.5M solution of Kcl
0.50 grams of BeCl2
5.50
I suppose that this solution doesn't exist.
1.5 moles
Put 100 grams in a beaker and and around 500 mls of water until it dissolves, then top up the beaker to a liter. That is your 10% solution. The percentage solution is a ratio of the weight of the compound to the weight of the final solution.
The answer is 7,5g.
1.47g
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
0.50 grams of BeCl2
5.50
The answer is 3,211 g.
93,31 g MgCl2 are needed.
I suppose that this solution doesn't exist.
148g
1.5 moles
newtest3
124,9 g grams of ammonium carbonate are needed.