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How many grams of CH3OH is needed to make 0.211m solution in 479g of water?
Wiki User
∙ 9y ago
The answer is 3,211 g.
Wiki User
∙ 8y ago
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How many grams of HF are needed to make 0.50L of a 0.750 M solution?
The answer is 7,5g.
How many grams of solid AgCl are needed to make 4.0 liters of a 5.0 M solution of AgCl?
newtest3
What is the mass (in grams) of 9.18 1024 molecules of methanol (CH3OH)?
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
What volume in ml of distilled water is needed to make 8.40 m of HCl acid using grams of HCl?
For 1 L solution 794,5 mL H2O are needed.
How many grams of NaOH are in 350 mL of a 5.7 M NaOH solution?
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 1.5 M CH3OH?
7,207 g methanol are needed.
How many grams of ch3oh must be added to water to prepare 150 ml of a solution that is 2.0 m ch3oh?
The answer is 9.6 grams.
How much NH3 is needed to react exactly with 21 grams of CH3OH?
CH3OH + NH3 → CH3NH2 + H2O 32 g of methanol reacts with 17.0 g ammonia 21 g of CH3OH react with 11.0 g NH3
What is the mass of 3.62 X 1024 molecules of CH3OH?
192.678 grams CH3OH
What is the mass in grams of 9.32x1024 molecules of methanol CH3OH?
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
What is the mass in grams of 9.03 X 1024 molecules of methanol CH3OH?
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
What is the mass (in grams) of 9.85x10 to the 24 of methanol (CH3OH)?
9,85x10 to the 24 of methanol (CH3OH) molecules have a mass of 52,405 g.
A solution has a density of 1.50 grams per milileter at 25.0 degrees Celsius How many grams are needed to obtain 5.00 ml of the solution?
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
How many grams of hydrochloric acid are needed to make a solution of 2 molar?
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution?
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
How many grams of beryllium chloride are needed to make 125 ml of a 0.050 m solution?
0.50 grams of BeCl2
How many grams of HF are needed to make 0.50L of a 0.750 M solution?
The answer is 7,5g.
