To calculate the amount of moles of potassium chloride in a 0.400 M KCl (aq) solution, you may use equation (1) below
n = c * v (1)
where n equals the amount of moles, c is the concentration of the solution and v is the volume.
We have the volume and the concentration, which renders us able to solve the equation:
n = 0.400 * 1.2 L
n = 0.48 moles.
.48 Moles
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
Ten milliliters is a hundredth of a liter. So in a two molar solution, you would have .02 moles in 10 ml.
2g
All of the moles of pure acid will have dissolved in the flask.
8 moles
Theoretically 16 moles but nitrogen monofluoride is unstable and I suppose that this solution cannot be prepared.
3 x 0.2 = 0.6 moles
2
We need 8 moles potassium chloride.
0.5 Moles If you have a 0.25 M solution, you have 0.25 mol/dm3, or 0.25 moles in 1 L (0.25 mol/L) If you have 2 L of solution, you have 2 L x 0.25 mol/L = 0.5 mol The L's cancel out, and you're left with moles.
The answer is 15,015 g.
This is a chemical calculation. there are 3.267 moles in this solution.
The number of moles is 0,527.
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
Hydrochloric acid is a mixture water: acid with different concentrations.For hydrogen chloride (HCl) you need 0,475 moles.