Ten milliliters is a hundredth of a liter. So in a two molar solution, you would have .02 moles in 10 ml.
Find moles potassium iodide first.2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KIMolarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )Molarity = 0.01452 moles KI/0.1 Liters= 0.145 M KI solution================
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.
1 gram NaCl (1 mole NaCl/58.44 grams) = 0.0171 moles NaCl Molarity = moles of solute/volume ( liters) of solution 0.171 M = 0.0171 moles NaCl/volume 0.1 Liters, or more to our point; 100 milliliters
there are two moles produced in potassium nitrate.
You have 4.8 moles and this is in 1.6 litres. 4.8 moles / 1.6 is 3 moles. This is also now 3 molar.
1,5 moles of potassium carbonate have 276,41 g.
The answer is 1,2 mol.
The amount of potassium phosphate in the solution is 1.27 M * 0.343 L = 0.43561 moles.The chemical formula of potassium phosphate is K3PO4, so there is three times as many moles of potassium as there are moles of potassium phoshate in the molecule:0.43561 * 3 = 1.30683Answer: 1.31 moles
0.1 moles
Molarity = moles of solute/Liters of solution ( 25 ml = 0.025 Liters ) 1.5 M KBr = moles KBr/0.025 Liters = 0.038 moles potassium bromide ------------------
0,052 moles
8.42 grams of KOH is equal to 0.15 moles. If the solution has a molarity of 2.26 moles per liter, then there are 66.4 milliliters of solution.
Depend on the kind of concentration it is expressed in. For a 1. 0.001 Molar solution, dissolve 0.001 mols of solute in enough solvent to obtain 1L of solution 2. 0.001 molal solution, dissolve 0.001 mols in 1kg of solution.
Find moles potassium iodide first.2.41 grams KI (1 mole KI/166 grams) = 0.01452 moles KIMolarity = moles of solute/Liters of solution ( 100 ml = 0.1 Liters )Molarity = 0.01452 moles KI/0.1 Liters= 0.145 M KI solution================
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.