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How many moles ok potassium are present in 343 mL of a 1.27 M solution of potassium phosphate?
Wiki User
∙ 16y ago
The amount of potassium phosphate in the solution is 1.27 M * 0.343 L = 0.43561 moles.
The chemical formula of potassium phosphate is K3PO4, so there is three times as many moles of potassium as there are moles of potassium phoshate in the molecule:
0.43561 * 3 = 1.30683
Answer: 1.31 moles
Wiki User
∙ 16y ago
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