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Q: How many moles of potassium hydroxide are required to make 200cm3 of 0.5M solution?
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What is the molarity of a solution made by dissolving 20g NaOH in 200cm3 of H20 help please?

Given that 200cm3 yieded 20g.therefore 22400cm3 which is the volume occupied by gas at s.t.p will contained:(22400cm3 times 20g) divided by 200cm3,which equals 2240g.but molarity is mass conc./molar mass,here molar mass of NaOH is 40.Hence the molarity is:2240/40 which equals to 56moles/g.


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200.0cm3 of 2.0 M K2SO4 solution are added to 800cm3 of water Find the molarity of the potassium ions in the resulting solution?

A fair question and some tricky points. Firstly, K2SO4 can be seen as 2K+[SO4]. If you put it into water, you get 2 potassium ions for each K2SO4. That's important. The rest is just wrestling with the numbers. We have 200cm3 of 2.0M K2SO4. How many moles is that? Well we'd have 2 moles in 1000cm3, so... (1000/200 = 5) we have 5 times less volume meaning 5 times fewer moles (2.0/5 = 0.4) so we have 0.4 moles K2SO4. Good. Now we put that into 800cm3 of water. There's a trick, here! It's not 0.4 moles into 800cm3 water, because our 0.4moles are ALREADY in their own 200cm3 of water. So remember to add the volumes up, too. But this just makes things so much easier for us! Because we end up with 1 litre which is the volume component of the molarity unit. (M = g/dm3 or g/L, same thing) So it's 0.4 moles of K2SO4 in 1litre of water, meaning 0.4M K2SO4. Finally....we want K+ ions, not K2SO4. Remember we had two K+ ions for every K2SO4? 2 x 0.4 = 0.8. So our answer is: we have 0.8M K+ solution in the end.


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1000 ml=10 cm3 so therefore 20,000 ml=200 cm3 1000 ml=1 L so therefore 20 L


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A rectangular prism that is 5 centimeters wide, 10 centimeters long and 4 centimeters high has a volume of 200cm3


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