Theoretically 16 moles but nitrogen monofluoride is unstable and I suppose that this solution cannot be prepared.
how many moles are there in 56.0 grams of silver nitrate?
8 moles
It depends on the concentration of HCl in the solution.
3 x 0.2 = 0.6 moles
It depends on the concentration of the solution. If you know the concentration(molarity) then use the equation. moles = [conc] x vol(mL) / 1000 NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.
Depends on the concentration of the solution and what is in it.
To calculate the amount of moles of potassium chloride in a 0.400 M KCl (aq) solution, you may use equation (1) belown = c * v (1)where n equals the amount of moles, c is the concentration of the solution and v is the volume.We have the volume and the concentration, which renders us able to solve the equation:n = 0.400 * 1.2 Ln = 0.48 moles.
All of the moles of pure acid will have dissolved in the flask.
how many moles are there in 56.0 grams of silver nitrate?
8 moles
This depends on the solution concentration.
It depends on the concentration of HCl in the solution.
This depends of the concentration of CaCl2 in this solution.
3 x 0.2 = 0.6 moles
It depends on the concentration of the solution. If you know the concentration(molarity) then use the equation. moles = [conc] x vol(mL) / 1000 NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.
2
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.