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It depends on the concentration of the solution.
If you know the concentration(molarity) then use the equation.
moles = [conc] x vol(mL) / 1000
NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.
What else can I help you with?
What is the final concentration of cl ion when 250 ml of 020 M cacl2 solution is mixed with 250 ml of 040 M kcl solution?
Start with CaCl2. 250ml of 0.20M solution will give (0.2/1000)*250 moles = 0.05 moles. However, CaCl2--> Ca2+ + 2Cl- (1:2 reaction) so 0.05moles of CaCl2 will give 2* 0.05 moles cl ions =0.1moles. KCl will give (0.4/1000)* 250 moles =0.1 moles Since KCl--> K+ + Cl- (1:1 reaction) so 0.1 moles KCl will give 0.1 moles Cl ions. Add the 2 together so 0.1moles + 0.1 moles = 0.2 moles in total.
How many grams of calcium chloride will you add to 250mL of water to make a 0.236 M solution?
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g
How many grams of the compound trinitrotoluene are needed to prepare 250 ml of a 0.100 M solution of the compound?
C7H5N3O6 Molarity = moles of solute/Liters of solution (250 ml = 0.25 Liters ) 0.100 M C7H5N3O6 = X moles/0.25 L = 0.025 moles -------------------------now, 0.025 moles C7H5N3O6 (227.14 grams/1 mole C7H5N3O6) = 5.68 grams TNT ====================a good firecracker!
How many grams of koh are needed to prepare 250 milliliters of a 2 m solution of koh formula mass 56?
To prepare a 2 M solution of KOH, you would need to calculate the moles of KOH required first. Then use the formula mass of KOH (56 g/mol) to convert moles to grams. First, calculate the moles needed: 2 moles/L * 0.25 L = 0.5 moles. Then, convert moles to grams: 0.5 moles * 56 g/mole = 28 grams of KOH needed.
What would be the concentration of a solution made by adding 250 ml of water to 45.0 m of 4.2 M KOH?
To find the final concentration, we calculate the moles of KOH initially present in the 45.0 ml solution, then add the moles from the additional 250 ml of water. We then divide the total moles by the final volume (45.0 ml + 250 ml) to get the concentration. The concentration of the final solution would be less than 4.2 M KOH due to dilution when water is added.
What is the final concentration of cl ion when 250 ml of 020 M cacl2 solution is mixed with 250 ml of 040 M kcl solution?
Start with CaCl2. 250ml of 0.20M solution will give (0.2/1000)*250 moles = 0.05 moles. However, CaCl2--> Ca2+ + 2Cl- (1:2 reaction) so 0.05moles of CaCl2 will give 2* 0.05 moles cl ions =0.1moles. KCl will give (0.4/1000)* 250 moles =0.1 moles Since KCl--> K+ + Cl- (1:1 reaction) so 0.1 moles KCl will give 0.1 moles Cl ions. Add the 2 together so 0.1moles + 0.1 moles = 0.2 moles in total.
A 230 mL sample of a 0.276 M CaCl2 solution was left on a hot plate overnight the following morning the solution is 1.10. What volume of water evaporated from the 0.276 M CaCl2 solution?
0.230 L X 0.276M CaCl2 = 0.0635 moles CaCl2 present in solution.Moles before dilution = moles after dilution0.0635 moles/V = 1.10 M CaCl2.V = 0.0577 L left in solution.0.230 L (original) - 0.0577 L (left over) = 0.172 L (evaporated)0.172 L = 172 mL
How many grams of calcium chloride will you add to 250mL of water to make a 0.236 M solution?
Molarity is moles of solute / liters of solvent. Plugging in the data: 0.236M = x / 0.250L; x = (0.236M)(0.250L) = 0.0590 moles of CaCl2. The molecular weight of CaCl2 is 40.1 + 2(35.5) = 111.1 g / mole. The mass of CaCl2 = (MW)(moles) = (111.1g/mole)(0.0590moles) = 6.55g
What is the final concentration of cl- ion when 250 ml of 0.20 M cacl2 solution is mixed with 250 ml of 0.40 M kcl solution?
To find the final concentration of Cl- ions, first calculate the moles of Cl- ions from each solution. Then add the moles of Cl- ions from both solutions and divide by the total volume of the mixed solution (500 ml) to get the final concentration. Using the formula C1V1 = C2V2 where C represents concentration and V represents volume, you can determine the moles of Cl- ions from each solution.
How many moles of sodium chloride are there in 250 mL of a 1.20 M sodium chloride solution?
To calculate the number of moles in a solution, use the formula: moles = Molarity x Volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (250 mL = 0.25 L). Then, plug the values into the formula: moles = 1.20 mol/L x 0.25 L = 0.30 moles of sodium chloride.
How many grams of the compound trinitrotoluene are needed to prepare 250 ml of a 0.100 M solution of the compound?
C7H5N3O6 Molarity = moles of solute/Liters of solution (250 ml = 0.25 Liters ) 0.100 M C7H5N3O6 = X moles/0.25 L = 0.025 moles -------------------------now, 0.025 moles C7H5N3O6 (227.14 grams/1 mole C7H5N3O6) = 5.68 grams TNT ====================a good firecracker!
750 ml of 20M HCl is mixed with 250 ml of 60M HCl What is the new molarity?
Molarity of a solution is the number of moles of the solute divided by the volume of the solution (in liters). If 750 ml of 20M HCl is mixed with 250 ml of 60M HCl, we first find the total number of moles of HCl in our new solution. Using that same formula, M=moles/V, we cansee that moles=MV. In the first solution we have (20M)(0.750L) = 15 moles. In the second, (60M)(0.250L) = 15 moles, so we have a total of 30 moles in our new solution, which also has a volume of 750mL + 250mL = 1L. The molarity of the new solution is 30 moles/1L = 30M
How many moles are in 250 g iron (III) oxide?
250 g iron (III) oxide is equal to 1,565 moles.
What is the molarity of 250cm3 sodium chloride solution containing 2 moles?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, there are 2 moles of sodium chloride in 250 cm^3, which is equivalent to 0.25 L. Therefore, the molarity of the solution is 8 M (2 moles / 0.25 L).
How many grams of koh are needed to prepare 250 milliliters of a 2 m solution of koh formula mass 56?
To prepare a 2 M solution of KOH, you would need to calculate the moles of KOH required first. Then use the formula mass of KOH (56 g/mol) to convert moles to grams. First, calculate the moles needed: 2 moles/L * 0.25 L = 0.5 moles. Then, convert moles to grams: 0.5 moles * 56 g/mole = 28 grams of KOH needed.
What would be the concentration of a solution made by adding 250 ml of water to 45.0 m of 4.2 M KOH?
To find the final concentration, we calculate the moles of KOH initially present in the 45.0 ml solution, then add the moles from the additional 250 ml of water. We then divide the total moles by the final volume (45.0 ml + 250 ml) to get the concentration. The concentration of the final solution would be less than 4.2 M KOH due to dilution when water is added.
How many grams of KCl would you need to make 250 ml of a 0.5-M Solution w work?
Molar mass of KCl = 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol. A 0.5 M solution is required (0.5 mol/L or 0.5 moles per litre). 0.5 moles of KCl is 0.5 mol x 74.5 g/mol = 37.25 g. Dissolving this 37.25 g of KCl in a litre of water would give a 0.5 M solution. If 1 L or 1000 mL of 0.5 M solution contains 0.5 moles then 1 mL of the same concentration solution would contain 0.5/1000 moles and 250 mL would contain 250 x 0.5/1000 moles = 0.125 moles. 0.125 moles of KCl is 0.125 mol x 74.5 g/mol = 9.31 g.
