3.65(g) / 65.38(g/mol) = 0.0558 (mol)
3.65 g Zn x 1 mole Zn/65.39 g = 0.0558 moles (3 sig. figs.)
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
3,80 g Zn have 0,058 moles.
I assume zinc limits in this reaction. Balanced equation. Zn + 2HCl -> ZnCl2 + H2 184 grams Zn (1 mole Zn/65.41 grams)(1 mole ZnCl2/1 mole Zn) = 2.81 moles zinc chloride produced ==========================
For this you need the atomic mass of Zn. Then take the mass in grams and divide it by the atomic number (multiplied by one mole for units to cancel) to find number of moles. Zinc's atomic mass is 65.4 grams.22.5 g Zn / (65.4 grams) = .344 moles Zn
136,315 g ZnCl are obtained.
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
3,80 g Zn have 0,058 moles.
I assume zinc limits in this reaction. Balanced equation. Zn + 2HCl -> ZnCl2 + H2 184 grams Zn (1 mole Zn/65.41 grams)(1 mole ZnCl2/1 mole Zn) = 2.81 moles zinc chloride produced ==========================
From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23. is this correct this is not the answer just a further question ...
For this you need the atomic mass of Zn. Then take the mass in grams and divide it by the atomic number (multiplied by one mole for units to cancel) to find number of moles. Zinc's atomic mass is 65.4 grams.22.5 g Zn / (65.4 grams) = .344 moles Zn
365 grams is 12.88 ounces.
Molar mass = 31+ 5(35.5) = 208.5 g/mole divide ... 35.6 g / 208.5 g/mole = 0.171 mole
4 g = 1 mole. So, 6.071 g = 1.52 mole
136,315 g ZnCl are obtained.
1 mole in 70 g of Cl2
4 g or helium is 1 mole. So, 0.12 g of helium is 0.03 mole
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============