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What is the amount in moles of 3.45 g Zn?
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
How many moles of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid?
I assume zinc limits in this reaction. Balanced equation. Zn + 2HCl -> ZnCl2 + H2 184 grams Zn (1 mole Zn/65.41 grams)(1 mole ZnCl2/1 mole Zn) = 2.81 moles zinc chloride produced ==========================
How many grams of ZnCl2 are formed from150 g of Zn and 73 g of HCl?
To determine the amount of ZnCl2 formed, we first need to find the limiting reactant. Zn is the limiting reactant in this case. The balanced chemical equation is: Zn + 2HCl -> ZnCl2 + H2. Using the given mass of Zn, calculate the moles of Zn, then use the mole ratio from the balanced equation to find the moles of ZnCl2 formed. Finally, convert the moles of ZnCl2 to grams.
How many moles does 3.80 g Zn have?
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
How many moles are in 3.60 g Zn?
To find the number of moles in 3.60 g Zn, you need to divide the mass by the molar mass of Zn. The molar mass of Zn is approximately 65.38 g/mol. So, 3.60 g Zn divided by 65.38 g/mol is equal to approximately 0.055 moles of Zn.
What is the amount in moles of 3.45 g Zn?
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
How many moles of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid?
I assume zinc limits in this reaction. Balanced equation. Zn + 2HCl -> ZnCl2 + H2 184 grams Zn (1 mole Zn/65.41 grams)(1 mole ZnCl2/1 mole Zn) = 2.81 moles zinc chloride produced ==========================
How many grams of ZnCl2 are formed from150 g of Zn and 73 g of HCl?
To determine the amount of ZnCl2 formed, we first need to find the limiting reactant. Zn is the limiting reactant in this case. The balanced chemical equation is: Zn + 2HCl -> ZnCl2 + H2. Using the given mass of Zn, calculate the moles of Zn, then use the mole ratio from the balanced equation to find the moles of ZnCl2 formed. Finally, convert the moles of ZnCl2 to grams.
How many atoms are in 7.1 mol Zn?
From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23. is this correct this is not the answer just a further question ...
How many moles does 3.80 g Zn have?
To find the number of moles in 3.80 g of Zn, you first need to calculate the molar mass of Zn, which is 65.38 g/mol. Then, divide the mass given (3.80 g) by the molar mass to get the number of moles, which is approximately 0.058 moles of Zn.
How many moles are in 3.60 g Zn?
To find the number of moles in 3.60 g Zn, you need to divide the mass by the molar mass of Zn. The molar mass of Zn is approximately 65.38 g/mol. So, 3.60 g Zn divided by 65.38 g/mol is equal to approximately 0.055 moles of Zn.
How many oz is 365 g?
365 grams is 12.88 ounces.
How many moles are in 22.5 grams of zinc?
For this you need the atomic mass of Zn. Then take the mass in grams and divide it by the atomic number (multiplied by one mole for units to cancel) to find number of moles. Zinc's atomic mass is 65.4 grams.22.5 g Zn / (65.4 grams) = .344 moles Zn
How many moles are in 125g of Zn?
The equivalent of 125 g zinc is 1, 91 moles.
How many grams of hydrochloric acid are reacted when 1.80 mol of zinc is reacted with 7.10 mol of hydrochloric acid?
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------
How many milliliters of 4.50 M HCl(aq) are required to react with 9.65 g of Zn(s)?
First, calculate the moles of Zn using its molar mass. Then, use the mole ratio from the balanced chemical equation between Zn and HCl to find the moles of HCl needed. Finally, use the molarity of HCl to calculate the volume in milliliters using the formula: Volume (mL) = moles / molarity.
Net ionic equation of reacting zinc with hydrochloric acid?
Zn (s) + 2H+ (aq) ------> Zn+2 (aq) + H2 (g)
