34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca)
= 13.8 grams calcium
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Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
To calculate the amount of CO formed from 35.0 grams of oxygen, you need to determine the limiting reactant. First, convert 35.0 grams of O2 to moles. Then, use the balanced equation to calculate the moles of CO that can be formed from the moles of O2. Finally, convert the moles of CO to grams using the molar mass of CO.
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
There is no compound with the formula CaCO the here is howver CaCO3 which is calcium carbonate. If the question was chemical names of Ca and CO then the answer is calcium and carbon monoxide
To convert 14.0 grams of CO into CO2, you need 16 grams of oxygen. This is because each molecule of CO reacts with one molecule of O2 to form one molecule of CO2. The molar mass of O2 is 32 g/mol, so 16 grams of oxygen is needed to convert 14.0 grams of CO.
There are 40.08 grams of calcium in 100 grams of CaCO3. To find the amount of calcium in 418 grams of CaCO3, you can set up a proportion and calculate that there are approximately 167.2 grams of calcium in 418 grams of CaCO3.
13.2g
160...cant quite grasp HOW though
0.87 g
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
To calculate the grams of CO needed to react with Fe2O3, you need to write a balanced chemical equation for the reaction, determine the moles of Fe2O3 given the mass provided, and use the stoichiometry of the balanced equation to find the moles of CO needed. Finally, convert the moles of CO to grams using the molar mass of CO.
To calculate the amount of CO formed from 35.0 grams of oxygen, you need to determine the limiting reactant. First, convert 35.0 grams of O2 to moles. Then, use the balanced equation to calculate the moles of CO that can be formed from the moles of O2. Finally, convert the moles of CO to grams using the molar mass of CO.
26,3 g cobalt is equivalent to 0,446 moles.
The answer is 445,6 g carbon dioxide.
5.34 grams W(CO)6 (1 mole W(CO)6/351.86 grams)(6 moles C/1 mole W(CO)6)(6.022 X 1023/1 mole C) = 5.48 X 1022 atoms of carbon ========================
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
There is no compound with the formula CaCO the here is howver CaCO3 which is calcium carbonate. If the question was chemical names of Ca and CO then the answer is calcium and carbon monoxide