13.2g
160...cant quite grasp HOW though
0.87 g
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
To calculate the grams of CO needed to react with Fe2O3, you need to write a balanced chemical equation for the reaction, determine the moles of Fe2O3 given the mass provided, and use the stoichiometry of the balanced equation to find the moles of CO needed. Finally, convert the moles of CO to grams using the molar mass of CO.
To calculate the amount of CO formed from 35.0 grams of oxygen, you need to determine the limiting reactant. First, convert 35.0 grams of O2 to moles. Then, use the balanced equation to calculate the moles of CO that can be formed from the moles of O2. Finally, convert the moles of CO to grams using the molar mass of CO.
26,3 g cobalt is equivalent to 0,446 moles.
The answer is 445,6 g carbon dioxide.
32 grams of water
5.34 grams W(CO)6 (1 mole W(CO)6/351.86 grams)(6 moles C/1 mole W(CO)6)(6.022 X 1023/1 mole C) = 5.48 X 1022 atoms of carbon ========================
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
If there is ample O2 then no CO will be produced, all the C will be made into CO2. You therefore need to make your question more precise regarding the proportions of the reactants present at the start if you want us to answer you.
To convert 14.0 grams of CO into CO2, you need 16 grams of oxygen. This is because each molecule of CO reacts with one molecule of O2 to form one molecule of CO2. The molar mass of O2 is 32 g/mol, so 16 grams of oxygen is needed to convert 14.0 grams of CO.