5.34 grams W(CO)6 (1 mole W(CO)6/351.86 grams)(6 moles C/1 mole W(CO)6)(6.022 X 1023/1 mole C)
= 5.48 X 1022 atoms of carbon
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Both samples contain the same number of carbon atoms because the number of atoms in a sample is determined by Avogadro's number (6.022 x 10^23) and not by the mass of the sample itself.
31.8 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C)= 1.59 X 1024 atoms of carbon===================
To calculate the number of carbon atoms in 2.50 grams of theobromine (C7H8N4O2), you first need to find the molar mass of theobromine. The molar mass of theobromine is 180.16 g/mol. From the molecular formula, there are 7 carbon atoms in one molecule of theobromine. Therefore, using the molar mass and the number of carbon atoms in the molecule, you can calculate the number of carbon atoms in 2.50 grams.
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
No, there are the same number of carbon atoms in 48g of CO2 and in 12g of diamond. This is because the atomic mass of carbon is the same, regardless of the molecule it is a part of.
17 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 8.5 X 1023 atoms of carbon =====================
The molar mass of carbon is approximately 12 g/mol. To find the mass of 7.8 x 10^18 carbon atoms, we first need to convert the number of atoms to moles by dividing by Avogadro's number (6.022 x 10^23 atoms/mol) and then multiply by the molar mass of carbon. The mass of 7.8 x 10^18 carbon atoms is approximately 1.6 x 10^-5 grams.
Atomic mass of carbon: 12.0 grams12.01 grams C × (6.02 × 1023 atoms) / (12.0 grams) = 6.03 × 1023 atoms of CarbonNote that one mole of any substance is Avogadro's constant (6.02 × 1023) and that one mole of Carbon is 12.0 grams. So if you have 12.01 grams of carbon (roughly one mole) you should get about Avogadro's constant.
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The answer is 13,367.1010e+23 atoms.
Not that much!! 4350000 atoms Carbon (1 mole C/6.022 X 10^23)(12.01 grams/1 mole C) = 8.675 X 10^-17 grams
9.00 grams carbon 13 ( 1 mole C13/13.00355 grams)(6.022 X 1023/1 mole C13) = 4.17 X 1023 atoms of carbon 13 -------------------------------------------