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The answer is 13,367.1010e+23 atoms.

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Q: How many carbon atoms are in 1.00 102 grams of trinitrotoluene an explosive?
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Which has more atoms 12 grams of carbon or 32 grams of carbon?

32g


How many carbon atoms are there in 31.8 grams of carbon?

31.8 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C)= 1.59 X 1024 atoms of carbon===================


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The number of carbon atoms is 0,588.10e23.


How many atoms are in 1.9 g Carbon?

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Are there more carbon atoms in 48g of CO2 than in 12 grams of diamond?

There are more carbon atoms in 48 grams of CO2 than in 12 grams of diamond


How many atoms are in 17 grams of carbon?

17 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 8.5 X 1023 atoms of carbon =====================


What is the mass of 7.8 x 1018 carbon atoms?

3.011 x 1023 atoms of carbon will weigh about 6 grams One mole of carbon atoms weighs 12.011 grams, and there are 6.022 x 1023 atoms in a moles. So you have half as many atoms, so the mass would be half as much or 6.0055 grams to be precise.


How many atoms in 12 grams of carbon?

Atomic mass of carbon: 12.0 grams12.01 grams C × (6.02 × 1023 atoms) / (12.0 grams) = 6.03 × 1023 atoms of CarbonNote that one mole of any substance is Avogadro's constant (6.02 × 1023) and that one mole of Carbon is 12.0 grams. So if you have 12.01 grams of carbon (roughly one mole) you should get about Avogadro's constant.


What is the mass, in grams, of 5.000 moles of carbon atoms?

0


What is the mass in grams of 4350000 atoms of carbon?

Not that much!! 4350000 atoms Carbon (1 mole C/6.022 X 10^23)(12.01 grams/1 mole C) = 8.675 X 10^-17 grams


How many atoms are in 9.00 grams of carbon 13?

9.00 grams carbon 13 ( 1 mole C13/13.00355 grams)(6.022 X 1023/1 mole C13) = 4.17 X 1023 atoms of carbon 13 -------------------------------------------


How many carbon atoms are in 2.6g of graphite pure carbon?

2.6 grams graphite ( just carbon ) (1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 1.3 X 1023 atoms of carbon in that mass graphite ================================