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From my understanding as there is only one mole of zinc which means the mass is 65.4 . Then to get the number of particles the answer is simply 1(the number of moles) x 6.02 x 10 ^ 23.
is this correct this is not the answer just a further question ...
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∙ 11y ago
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∙ 12y agoMass = (mol)*(mol mass) = 1.140 (mol) * 65.38 (g/mol Zn) = 74.53 g Zn
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∙ 15y ago0,1377 x 65,4 = 9 grams of zinc
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∙ 9y ago65.3800 g/mol
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∙ 9y agoOne mole of zinc is 65.38 grams.
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∙ 13y ago65.39g
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How many atoms of zinc are there in 135 gms?
135 grams zinc (1 mole Zn/65.41 grams)(6.022 X 10^23/1mole Zn) = 1.24 X 10^24 atoms of zinc
How to Calculate the mass in amu of 2500 atoms of Zn?
amu = 1.66 X 10^-27 kg Find mass of 2500 atoms Zn in kg. 2500 atoms Zn (1mole Zn/6.022 X 10^23)(65.41 grams/1 mole Zn)(1 kg/1000 g) = 2.72 X 10^-22 kilograms/1.66 X 10^-27 = 1.64 X 10^5 amu
How many grams of hydrochloric acid are reacted when 1.80 mol of zinc is reacted with 7.10 mol of hydrochloric acid?
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------
What is the number of atoms in 12G zinc?
12 grams zinc (1 mole Zn/65.41 grams)(6.022 X 1023/1 mole Zn) = 1.1 X 1023 atoms zinc ==================
If you have 25g of Zinc and 300g of Sulfur what is the mass of the excess reactant?
Zn + S ==> ZnSmoles Zn = 25 g x 1 mol/65.4 g = 0.38 moles Znmoles S = 300 g x 1 mol/32 g = 9.38 moles Smoles S in excess = 9.38 - 0.38 = 9.00 molesmass S in excess = 9 moles x 32g/mol = 288 g = 280 g (to 2 significant figures)
What is the answer. Determine the number of atoms in 3.29 mol Zn?
3.29 moles Zn x 6.02x10^23 atoms/mole = answer (do the math)
How many atoms of zn are in 5 moles?
8
How many Zn atoms are in Zn(CIO3)2?
1
How many atoms are in 1 mole of zinc atoms?
3 moles of Zn is equal to 18.09x1023 atoms. I used Avogadro's Number : 6.03x1023 particles/mol This number is the number of atoms or molecules in a mol of any substance. 3 moles X 6.03x1023 particles/mol = 18.09x1023 atoms
How many zinc atoms are present in 20.0 g Zn?
Molar mass of Zinc = 65.4 g mol-1 No. of moles of 20.0 g of Zinc = 20.0 / 65.4 = 0.305810397 mol No. of atoms = 0.305810397 L (where L is the Avogadro constant) = 1.8416 x 1023
How many mole in 3.65 g Zn?
3.65(g) / 65.38(g/mol) = 0.0558 (mol)
How many atoms Zn atoms are in Zn(ClO3)2?
There are : 1 zinc atom 2 chlorine atoms 6 oxygen atoms in this zinc chlorate molecule.
What is the number of atoms in 1.88 moles of Zn?
1.88 mol Zn ( 6.022 X10^23/1mol Zn ) = 1.13 X10^24 atoms.
How many moles of hydrogen are produced from the reaction of three moles of zinc with an excess of hydrochloric acid?
I assume zinc limits in this reaction. Balanced equation. Zn + 2HCl -> ZnCl2 + H2 184 grams Zn (1 mole Zn/65.41 grams)(1 mole ZnCl2/1 mole Zn) = 2.81 moles zinc chloride produced ==========================
How many moles of copper will be produced if 5.8 mol of Zn react with excess copper II sulfate?
Also 5,8 mol
How many CI atoms are in Zn?
For Apex the answer is 2
.25 g of zinc reacted with 10 mL of HCl what is the moles of zinc reacted?
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn
