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d=50m Vi=90km/h(25 m/s) Vf=0

changing km/h to m/s--> 90x1000/3600= 25

Use: Vf^2= Vi^2+2ad

0^2= 25^2+ 2a50

= -81 m/s^2

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Q: A sports car is advertised to be able to stop in a distance of 50 m from a speed of 90 What is its acceleration in m-s 2 how many G's is this?
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