A sports car is advertised to be able to stop in a distance of 50 m from a speed of 90 What is its acceleration in m-s 2 how many G's is this?

Answer 1

d=50m Vi=90km/h(25 m/s) Vf=0

changing km/h to m/s--> 90x1000/3600= 25

Use: Vf^2= Vi^2+2ad

0^2= 25^2+ 2a50

= -81 m/s^2

Answer 2

To calculate the acceleration, we can use the equation (a = \frac{v^2}{2d}), where (v) is the initial velocity (90 m/s) and (d) is the distance (50 m). Plugging in the values, we get an acceleration of 8.1 m/s^2. To convert this to G's, we divide by the acceleration due to gravity (9.81 m/s^2), giving us approximately 0.83 G's.