A stone falls freely from rest The total distance covered by it in the last second of its motion equals the distance covered by it in the first three seconds How long does the stone remain in air?
0.7848 meter
490 meters
78.46 meters (257.4 feet)
a nswer
a nswer
A handy formula for distance covered from rest with constant acceleration in time 'T':D = 1/2 a T2D = (1/2) (9.8) (5)2 = 122.5 meters
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
With the information given, all that can be said is that the distance is greater than the distance the object traveled in the previous second.
78.4 m/s
A joint in which the opposing bony surfaces are covered with a layer of hyaline cartilage or fibrocartilage and in which some degree of free movement is possible.
5*9.8 = 49 metres per second.
98 meters (322 feet) per second.