With the information given, all that can be said is that the distance is
greater than the distance the object traveled in the previous second.
false
0.7848 meter
Yes, an object freely falling still has mass. Mass is a measure of the amount of matter in an object, and it remains constant regardless of the object's motion. The force of gravity acting on the object is what causes it to fall.
For objects falling under constant acceleration (such as gravity), the distance an object travels each second is determined by the formula d = 0.5 * a * t^2, where "d" is the distance, "a" is the acceleration, and "t" is the time in seconds. This means that the distance traveled each second will increase quadratically as time passes.
x = 1/2 g t2 = (4.9) (10)2 = 490 meters
You can increase the time of descent of a freely falling body by increasing its initial height from which it falls. This will give it more distance to cover before reaching the ground, thereby increasing the time it takes to fall. Additionally, you can increase air resistance by changing the shape or size of the falling object, which will also increase the time of descent.
Gravity is forcing an object to fall to the ground. Another force is friction from air pressure on the falling object.
It accelerates at a higher rate
The formula for calculating the velocity of an object falling freely under gravity is v2/2g, where v represents the velocity of the object and g represents the acceleration due to gravity.
The distance an object travels in a certain period of time is determined by its speed and the duration of time it is moving. The distance traveled can be calculated using the formula distance = speed x time.
The constant for an object falling freely towards the Earth is the acceleration due to gravity, which is approximately 9.8 m/s^2. This acceleration remains the same regardless of the mass of the object, resulting in all objects falling at the same rate in a vacuum.
The vertical distance an object falls can be calculated using the formula ( d = \frac{1}{2} g t^2 ), where ( d ) is the distance fallen, ( g ) is the acceleration due to gravity (approximately ( 9.81 , \text{m/s}^2 ) on Earth), and ( t ) is the time in seconds that the object has been falling. This formula assumes that the object is falling freely under the influence of gravity, with no air resistance.