Ignoring atmospheric pressure, overall pressure is equivalent to the specific weight of the liquid times the depth. Water has a density of 1 kg/m3 and gravity has a force of 9.81 m/s2. So specific weight = density * gravity = 9.81 kg/m2s2. When multiplied by 4 meters, the answer is 39.24 Pascal's. (1 Pascal = 1kg/ms2).
The pressure at the bottom of the tank can be calculated using the formula P = ρgh, where P is pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the height of the water column. For water, the density is approximately 1000 kg/m^3 and gravitational acceleration is 9.81 m/s^2. Plugging in the values, the pressure at the bottom of the tank would be around 34 kPa.
P=hight * density *gravity
p=3.5*1000*9.8
to find the answer in kPa its going to be 34.3
39.2 kpa
The pressure at any point at the bottom of the tank is determined by the height of the water column above that point. The pressure is given by the formula P = ρgh, where ρ is the density of water (around 1000 kg/m^3), g is the acceleration due to gravity (around 9.81 m/s^2), and h is the height of the water column (3.5 meters in this case). Plugging in these values will give you the pressure at the bottom of the tank.
The pressure at the bottom of the tank can be calculated using the formula P = ρgh, where ρ is the density of water (1000 kg/m³), g is the acceleration due to gravity (9.81 m/s²), and h is the height of the water column (4 meters). Plugging in these values, we get P = 1000 * 9.81 * 4 = 39240 Pa, or 39.24 kPa.
The pressure at the bottom of the tank is determined by the weight of the water above that point. To calculate the pressure, you would use the formula P = ρgh, where P is pressure, ρ is density, g is acceleration due to gravity, and h is the height of the water column. Given the height is 4 meters and water density is 1000 kg/m^3, you can calculate the pressure.
The pressure at any point at the bottom of the tank is determined by the height of the water above that point. The pressure is calculated as the product of the density of water, acceleration due to gravity, and the height of water above the point. The pressure increases with depth, so the pressure at the bottom of the tank would be higher than at a point higher up in the tank.
The pressure at any point at the bottom of the tank can be calculated using the formula P = ρgh, where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the height of the water column above the point. Plugging in the values for water density (1000 kg/m^3), acceleration due to gravity (9.81 m/s^2), and height (4 meters), the pressure at the bottom of the tank is approximately 39,240 Pascal or 39.24 kPa.
The pressure at the bottom of the tank can be calculated using the formula P = ρgh, where ρ is the density of water (1000 kg/m³), g is the acceleration due to gravity (9.81 m/s²), and h is the height of the water column (4 meters). Plugging in these values, we get P = 1000 * 9.81 * 4 = 39240 Pa, or 39.24 kPa.
The pressure at any point at the bottom of the tank is determined by the height of the water column above that point. The pressure is given by the formula P = ρgh, where ρ is the density of water (around 1000 kg/m^3), g is the acceleration due to gravity (around 9.81 m/s^2), and h is the height of the water column (3.5 meters in this case). Plugging in these values will give you the pressure at the bottom of the tank.
approximately 0.8 bar
The pressure at any point at the bottom of the tank is determined by the weight of the water above that point. It is given by the formula P = ρgh, where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the height of the water column. So, the pressure at the bottom of the tank would be ρgh = (1000 kg/m^3)(9.81 m/s^2)(4 m) = 39,240 Pa.
c-34.3kpa
The pressure at the bottom of the tank is determined by the weight of the water above that point. To calculate the pressure, you would use the formula P = ρgh, where P is pressure, ρ is density, g is acceleration due to gravity, and h is the height of the water column. Given the height is 4 meters and water density is 1000 kg/m^3, you can calculate the pressure.
The pressure at any point at the bottom of the tank is determined by the height of the water above that point. The pressure is calculated as the product of the density of water, acceleration due to gravity, and the height of water above the point. The pressure increases with depth, so the pressure at the bottom of the tank would be higher than at a point higher up in the tank.
The pressure at any point at the bottom of the tank can be calculated using the formula P = ρgh, where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the height of the water column above the point. Plugging in the values for water density (1000 kg/m^3), acceleration due to gravity (9.81 m/s^2), and height (4 meters), the pressure at the bottom of the tank is approximately 39,240 Pascal or 39.24 kPa.
Ignoring atmospheric pressure, overall pressure is equivalent to the specific weight of the liquid times the depth. Water has a density of 1 kg/m3 and gravity has a force of 9.81 m/s2. So specific weight = density * gravity = 9.81 kg/m2s2. When multiplied by 4 meters, the answer is 39.24 Pascal's. (1 Pascal = 1kg/ms2).
1.5
Pressure is given by the formula -pgh , where p= desity of water , g gravity ,and h height . So pressure at the depth 3.5m =1*9.8*3.5 pa =34.3 pa. (Assuming density of water to be 1).
It depends on whether the pipe is open or closed and what it contains. If the pipe is full of water to a height of 40 m and open at the top, the pressure at the bottom is about 57 psig. The diameter doesn't matter.