3.5kpa
Since we are ignoring atmospheric pressure, the pressure at the bottom of the tank is given by p = dgh. Where d equals density, g is acceleration of gravity, and h is the height below the fluid surface. In this case, the density of water is 10^3 kg/m^3, the acceleration of gravity is 9.8 m/s^2, and the height is 4 m. This means the pressure is 39.2 kPa.
liquid density
P=pgh, remeber that g=9.8 , so ignoring the atmosheric pressure you would just multiply 9.8x4 and you would get 39.2KPa ... i'm not that good with physics so just analyze what is given to you and figure out if the answer is correct or not. Hope I helped :)
the answer isC. 34.3 kPa
The pressure at the bottom of the bottle is the greatest. It decreases as the level comes up and is the least at the top.
Elephant. :)
the atmospheric pressure
Since we are ignoring atmospheric pressure, the pressure at the bottom of the tank is given by p = dgh. Where d equals density, g is acceleration of gravity, and h is the height below the fluid surface. In this case, the density of water is 10^3 kg/m^3, the acceleration of gravity is 9.8 m/s^2, and the height is 4 m. This means the pressure is 39.2 kPa.
Ignoring atmospheric pressure, overall pressure is equivalent to the specific weight of the liquid times the depth. Water has a density of 1 kg/m3 and gravity has a force of 9.81 m/s2. So specific weight = density * gravity = 9.81 kg/m2s2. When multiplied by 4 meters, the answer is 39.24 Pascal's. (1 Pascal = 1kg/ms2).
liquid density
P=pgh, remeber that g=9.8 , so ignoring the atmosheric pressure you would just multiply 9.8x4 and you would get 39.2KPa ... i'm not that good with physics so just analyze what is given to you and figure out if the answer is correct or not. Hope I helped :)
because the other half is not empty it is filled with gas
10.85 psi.
the same amount of molcules in each A+
the answer isC. 34.3 kPa
The pressure at the bottom of the bottle is the greatest. It decreases as the level comes up and is the least at the top.
No, just an inert gas and mercury vapor at close to atmospheric pressure. Without the inert gas it would be near vacuum, as very little mercury is needed.