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A train accelerates from 30 km per hr to 45 km per hr in 15 seconds Find its acceleration and distance?
Wiki User
∙ 14y ago
By kmh you probably mean km/h. If so, (40-35)km/h=(45-40)km/h=(50-45)km/h=5km/h is the change in velocity each second and (5km/h)= (5km/h)(1h/3600s)=0.0013888889km/s=(0.00138km/s)(1000m/km)=about 1.38m/s and the acceleration is the change in velocity divided by the change in time. The acceleration is then a=(1.38m/s)/1s=about 1.38m/s2.
Wiki User
∙ 16y ago
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If the speeding train hits the brakes and it takes the train 39 seconds to go from 54.8 ms to 12 ms what is the acceleration?
if a speending train hits the brakes and it take the train 39bseconds to go from 54.8 m/s to 12 m/s what is the acceleration
What unit of measurement do you use to measure the length of a journey on a train?
depends on which country you are in...mostly traveling distance is measured in km or miles. 1 mile = 1.6 km
A train travels at a speed of 30 miles per hour If 1 mile equals 1.6 kilometers how fast is the train traveling in kilometers per minute?
You start by converting that to kilometers per hour, which would be 48 kilometers per hour. An hour contains 60 seconds, and to convert to smaller units of time, you divide, so 48/60 is 0.8 kilometers per minute.
In the 1950s an experimental train that had a mass of 2.50 X 104 kg was powered across a level track by a jet engine that produced a a thrust of 5.00 X 105 N for a distance of 509 m Find the work?
(5*105N)*509m=267225Nm Force times distance = Work (Work = Energy) Power = Work / Time
How height is a train?
Freight train height is 12-13 ft tall.Subway or underground train height is 10 ft tall
What is the final velocity of a train that starts at rest and accelerates for 15.0 seconds at an average acceleration of 2.40 meter per second squared?
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
If a train is traveling at 50 feet per second and experiences an acceleration of 10 feet per second how many seconds will it take to stop?
Well if it accelerates, it speeds up so it won't stop. If you mean decelarate, it decreases 10 ft/s every second, so 50/10 is 5 seconds
If the speeding train hits the brakes and it takes the train 39 seconds to go from 54.8 ms to 12 ms what is the acceleration?
if a speending train hits the brakes and it take the train 39bseconds to go from 54.8 m/s to 12 m/s what is the acceleration
A train initially stationary has a constant acceleration of 0.5 Miles per second what is the speed after fifteen seconds?
7.5
A train approaching a crossing changes speed from 25 meters per second to 10 meters per second in 240 seconds how can the train's acceleration be described?
Acceleration = (change in speed) / (time for the change)= (10 - 25) / 240 = -15/240 = -0.0625 meter/sec2The acceleration is negative, which is a description of slowing down.
After stopping at a station a train accelerates at a steady rate of 0.25ms-2 At what speed is the train moving after it has traveled 1.0 km?
Using v2 - u2 = 2as where, v = final velocity u = initial velocity a = acceleration s = distance travelled we get v2 = u2 + 2as Substituting the values, we get v2 = 02 + (2 x 0.25 x 1000) so v2 = 500, therefore v = 22.36 The train will be travelling at 22.36 ms-1.
A train went 4000m in 125 seconds how fast was it going?
To cover 4000 metres in 125 seconds the train would be travelling at 71.58 miles an hour. This is the speed over the whole measured distance and not from a standing start
Two trains leave a station at the same time train A travels at a constant of 16ms train B starts at 8.0 ms but accelerates constantly at 1o ms After 10.0 seconds which train has the greater speed?
Do your own homework! The train travelling at the constant speed will still be doing 16ms after 10 seconds The other train adds 1m per second so, after 10 seconds it will have added 10, 10 + 8 = 18ms. It is going faster. or : you can find the final velocity : final velocity = vi+a(t) = 8+1(10) =18 m/s So Train B is faster.
Compare the tension of a train with constant speed and acceleration?
Unless the train is in a curve, you cannot have constant speed and constant acceleration. You either have constant speed and zero acceleration, or you have changing speed and constant acceleration. Please restate the question.
Can A 150 m long train crosses a bridge that is 850 m long in 100 seconds What is the total distance traveled by the train What is the speed of the train?
To totally cross the bridge the train must travel (850m + 150m) 1 km. 1 km in 100 seconds is 10 m/s roughly 20 mph, so the answer is yes, with ease.
What distance would be covered in 12 minutes by a train that travels at a constant speed of 505 meters every 11 seconds?
33,055m or 33.055Km
What is the maximum acceleration of a train travelling at 90 miles per hour?
The speed or velocity of a train has no bearing on its acceleration.
