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draw yourself a triangle, with a 90* angle at the root of the tree. The sides of the triangle are: The shadow(the base side), the tree (the vertical side) and the distance between the top of the tree and the top of the shadow of the tree (the diagonal side).
Then either calculate the diagonal side and solve the puzzle with a sine or directly solve it with a cosine. (You need the angle between the diagonal and base sides)

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Q: A tree 10 ft tall cast a shadow 12 ft long find the angle elevation of the sun.?
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Related questions

How can you find the height of tree?

Using trigonometery if you know the length of its shadow and angle of elevation


How do you find the elevation of the sun?

WARNING: Do not, under any conditions, look at the sun, directly or indirectly.The find the elevation of the sun, measure the angle that an object's shadow from the sun makes. One way to do this is with a stick in the ground. Assuming the stick is perpendicular to the ground, the ratio of the stick's length to the shadow's length is the tangent of the angle of elevation. Solve for inverse tangent, and you have the angle.


How do you find the Angle Of Sun When Tree Is 6.25m And The Shadow Is 10.1m Long?

Use the tangent angle of elevation which works out as 31.7497 degrees to four decimal places


How do you find the angle of elevation from the tip of the shadow of a 12 foot flag pole to the top of the pole is 60 degrees?

is that the entire question because you already gave the angle, meaning you now have every angle for the triangle created by the pole and shadow


Find the angle of elevation of the sun when a flagpole 22.5 m high casts a shadow 34 m long?

Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''


How do you find the angle of elevation of the sun if the shadow of the pole 60 ft tall reaches 92 ft from the pole?

Providing that the pole is on level ground you have the outline of a right angled triangle with an adjacent side of 92 ft (the shadow of the pole) and a opposite side of 60 ft (the height of the pole). To find the angle of elevation use the tangent ratio. Tangent = Opposite/Adjacent Tangent = 60/92 = 0.652173913 Tan-1(0.652173913) = 33.11134196 degrees Therefore the angle of elevation is 33o correct to two significant figures.


How do you find the adjacent side of the angle of elevation of a right triangle if you have the angle of elevation and height?

i dont care about math even though i use it.


At a certain distance the angle of elevation to the top of a building is 60 From 40ft further back the angle of elevation is 45 Find the height of the building?

Angle of elevation: tangent angle = opposite/adjacent and by rearranging the given formula will help to solve the problem


A lamp pole casts a shadow 49 feet long when the angle of elevation of the sun is 44.8 degrees Find the height of the lamp pole?

A pole casting a shadow 49 feet long with an angle of elevation of the sun of 44.8 degrees is 50 feet tall. (47.98 rounded to two places)Tangent (theta) = opposite / adjacentTangent (44.9) = X / 49X = 47.98This does not take into account the curvature of the earth, but the error in this example is inconsequential, specifically an elevation error of about 0.015 percent.


Simple angle of elevation word problem?

A simple angle of elevation problem...You want to find out the height of a tree. You measure the distance from you to the base and find that it is 100 feet. You measure the angle of elevation of the top and find that it is 30 degrees. You are six feet tall. How tall is the tree?Answer: The tree is 64 feet tall. Its height is tangent 30 times 100 + 6.


At a certain time of day the angle of elevation of the sun is 30 degree A tree has a shadow that is 25 feet long Find the height of the tree to the nearest foot?

Tan60= 25/Height. Height = 25/Tan60 = 14.43


A tree casts a shadow of 23 meters when the angle of elevation of the sun is 23 Find the height of tree to the nearest meter?

Use the tangent ratio: 23*tan(23) = 9.762920773 Answer: 10 meters to the nearest meter