Ratio of object to its shadow is the same.
So if T is the height of the tree, then T/21 = 4/6
So T = 21*4/6 = 84/6 = 14 feet
h = height of tree 150 / 20 = h / 2 h = (150/20) X 2 h = ? (you figure it out)
Shadow lengths are proportional to the heights of objects casting the shadows. Therefore, calling the shadow length l, the height h, and the proportionality constant k, l = kh. (The intercept is 0 because an object with no height casts no shadow.) Therefore, in this instance k = l/h = 6/3 or 8/4 = 2. then l(6) = 2 X 6 = 12 feet.
The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
Assuming the shadows are measured at the same time of day and that the trees are on level ground, the tree with a 20-foot shadow is a quarter longer than the tree with a 16-foot shadow. Adding a quarter of the height to 12 feet makes it 15 feet tall. Alternatively use the tangent ratio which will be opposite (height of 1st tree) over adjacent (its shadow) and multiply it by the adjacent of the 2nd tree: (12/16)*20 = 15 feet tall.
10.08 feet approx.
2
A 1 foot shadow I think.
It is 90 feet in height
Using trigonometry its height is 12 feet
The height of the flagpolle is 26.25 feet
It works out as 12 feet and 4 inches in height
It depends on the time of day because the angle of the sun will determine the shadow length
Height of building/105 = 6/14 Multiply both sides by 105: Height = 630/14 Height = 45 feet
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
(12 / 5) × 33 = 79.2 feet high Divide the pole shadow by the pole height: (12 / 5) = 2.4 feet Times the 2.4 by the tree shadow of 33 feet: 2.4 x 33 = 79.2
28 feet
If you mean the height of the building then it works out as 466.5063509 feet