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Using the acceleration formula,

final acceleration is the final velocity minus the initial velocity over elapsed time.

Final velocity you gave as 40m/s, and the initial velocity was zero (the apple was stationary on the tree), so the difference is 40 m/s. Divided by the time you gave, 4 s, this will be 10 m/s²

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Related Questions

Will the velocity of an object increase decrease or remain constant as it reaches the ground?

The velocity of an object will increase as it falls towards the ground due to the acceleration of gravity. However, once it reaches terminal velocity, its velocity will remain constant.


A rock is dropped from a height of 60 m and is in free fall. What is the velocity of the rock as it reaches the ground 3.5 seconds later?

The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.


A skydiver steps from a helicopter and falls for 5 seconds before reaching her terminal velocity during this 5 second interval her acceleration?

is constantly decreasing until it reaches zero when she reaches terminal velocity. At that point, her acceleration is zero and she falls at a constant speed, experiencing air resistance equal in magnitude to her weight.


A ball is dropped from a window and takes 2 seconds to reach the ground. It starts from rest and reaches a final speed of 20 MS What is the balls acceleration?

The acceleration of the ball can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the initial velocity is 0 m/s, the final velocity is 20 m/s, and the time is 2 seconds. Therefore, the acceleration would be (20 m/s - 0 m/s) / 2 s = 10 m/s^2.


A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant before it hits the ground?

To calculate the velocity of the ball just before it hits the ground, we can use the equation of motion: velocity = acceleration x time. The acceleration due to gravity is approximately 9.8 m/s^2. Given the time of 3.0 seconds, we can plug these values into the equation to find the velocity. Therefore, the velocity of the ball just before it hits the ground is 29.4 m/s.


Does the velocity of a falling object increase or decrease?

The velocity of a falling object increases as it falls due to the acceleration of gravity acting on it. As the object falls, it gains speed and accelerates toward the ground until it reaches a constant velocity known as terminal velocity.


If the velocity of a particle is nonzero can the particle's acceleration be zero?

yes. If the forces acting on the a moving particle are in equilibrium, (e.g. when a spherical object reaches terminal velocity (neglecting increased air resistance as it gets closer to the ground)) then the particle will be moving at a velocity, that is not 0, yet the velocity will remain constant, and the body will not accelerate or decelerate in any direction, and thus the acceleration is 0.


What is the velocity of a ball that has a 3.03 second hit to the ground?

If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.


A penny that was dropped hit the ground in 4.5 seconds what was the velocity of the penny?

The velocity of the penny when it hits the ground can be calculated using the formula: velocity = acceleration due to gravity x time taken to fall. The acceleration due to gravity is roughly 9.81 m/s^2. Therefore, the velocity of the penny when it hits the ground is 44.145 m/s.


When is acceleration neg?

Acceleration is negative if velocity is decreasing with time. Since velocity is a vector this can occur in one of two ways: 1) you are slowing down in the direction of motion and the velocity in that direction is defined as positive (this is what we usually mean by negative acceleration) 2) you are speeding up in the direction of motion and the velocity in that direction is defined as negative. An example of this is an object launched into the air which immediately starts to decelerate in it's upward velocity, reaches it's highest velocity, and then begins accelerating towards the ground. If we call the velocity upward a positive velocity, then when it starts falling, it has negative velocity. Note that acceleration (due to gravity) is negative the whole time.


Is there a graph of the acceleration rate of a falling object?

Yes, the acceleration rate of a falling object can be graphed over time. The graph typically shows the acceleration increasing due to gravity until it reaches a constant value (9.8 m/s2) once the object reaches terminal velocity or lands on the ground.


A rock is dropped from a height of 30 m and is in free fall What is the velocity of the rock as it reaches the ground 2.5 seconds later?

There are several ways to solve this. An elegant way is using conservation of energy: If you neglect air resistance, after dropping 30 meters, all the potential energy is converted to kinetic energy. So, just calculate the potential energy at the top, assume the kinetic energy at the bottom is the same value, and solve the kinetic energy equation for speed.