0
An airplane needs to reach a velocity of to take off. On a runway what is the minimum acceleration necessary for the plane to take flight Assume the plane begins at rest at one end of the runway.?
Wiki User
∙ 7y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
An airplane must reach a speed of 195 miles hour to take off if the the runway is 456 meter long what is the minimum value of the acceleration that will allow the airplane to take off successfully?
The change in velocity is the integral of acceleration with respect to time. Assuming a constant acceleration, thenv = integral [a dt] = a t + v0The change in distance is the integral of velocity with respect to time:s = integral (v dt) = integral [(at + v0) dt] = 1 /2 a t^2 + v0 t + s0Since the airplane is taking off from standing still at the start of the runway, s0 = 0 and v0 = 0.s = 1/2 a t^2We know that the at the end of the runway (456 m), the velocity must be 195 mph or 87.2 m/s, and this is v = at for constant acceleration. Plugging this in, we get:456 m = 1/2 (87.2 m/s) tSolving for t we get t = 10.5 secondsPlugging this back into the equation for s, then456 m = 1/2 a (10.5 s)^2Solving for a:a = 8.27 m/s^2
What is the minimum magnitude of acceleration?
Zero is.
How do you find distance with final velocity and minimum acceleration?
vf2 = vi2 +ad, where vf is the final velocity, vi is the initial velocity, a is acceleration, and d is displacement. In physics, velocity is the change in position of an object over a given time interval, and change in position is displacement, rather than distance. To find displacement, manipulate the equation in the following manner. Assume vi is zero. vf2 = 0 + 2ad vf2 = 2ad vf2/2a = 2ad/2a vf2/2a = d
What is the minimum acceleration for a particle in simple harmonic motion obeying x equals acos2t?
Acceleration is a vector, so it has both magnitude and direction.A particle in the simple harmonic motion, x = a cos(2t), has an acceleration that varies between positive and negative extremes (+4a and -4a) at the end points of its motion and has zero acceleration as it passes through its center of motion.Here is the mathematics.Position ' x ' = a cos(2t)Velocity ' v ' = dx/dt = -2a sin(2t)Acceleration = dv/dt = -4a cos(2t)The minimum instantaneous magnitude of acceleration is zero,and its most negative instantaneous value is [ -4a ].
Is orbital velocity the velocity a rocket must reach to fly off into space?
No.Orbital Velocity is the velocity required by a body to achieve a circular orbit around its primary.Escape velocity is the minimum velocity needed to escape a gravitational field
What does the term 'escape velocity' mean?
Escape velocity is what a moving body has to achieve in order not to be pulled back down to the planet. For Earth it is about 7 miles per second.
An organization should limit the use or disclosure of PHI to the minimum necessary to accomplish the intended purpose?
Minimum Necessary Standard
What does minimum necessary standard?
An organization should limit the use or disclosure of PHI to the minimum necessary to accomplish the intended purpose
Minimum necessary standard?
An organization should limit the use or disclosure of PHI to minimum necessary to accomplish the intended purpose.
What is an organization that should limit the use or disclosure of PHI to the minimum necessary to accomplish the intended purpose?
Minimum Necessary Standard
What does minimum necessary standard mean?
An organization should limit the use or disclosure of PHI to the minimum necessary to accomplish the intended purpose
What means Minimum Necessary Standard?
An organization should limit the use or disclosure of PHI to the minimum necessary to accomplish the intended purpose
